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tiny-mole [99]
3 years ago
13

Which statement outputs a double value in a field of nine characters with three digits after the decimal point?

Computers and Technology
1 answer:
zimovet [89]3 years ago
3 0

Answer:

Console.WriteLine("Format Double: {0:n3}", num); //formatting output with 3 digit decimal point

Explanation:

Following are the program in c#

using System; // namespace  

using System.Collections.Generic;

using System.Linq;

using System.Text;

namespace Tasks

{

   class Program 2 // program2

   {        

                 

       static void Main(string[] args) // Main function

       {

 

           double num = 958254.73789621;   // variables          

           Console.WriteLine("Format Double: {0:n3}", num); //formatting output with 3 digit decimal point

           Console.Read();

       }

   }

}

Output:

Format Double : 958254.737

Here we have declared  a variable num of type double which store the value num=958254.73789621. To do format with the double number i used a syntax {0:n3}. This syntax {0:n3}is separated with :(colon) here 0 represent the value before the decimal point that is 958254 and n3 represent the value upto 3 decimal points. Hence this statement give the output with three digit after the decimal point .

 

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b. If the file ends with 2 \n

c. If the file ends with 1 \n

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