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tester [92]
3 years ago
15

Fitness Classes cost £6 per person. The table shows the number of people who go to the classes on Thursday, Friday and Saturday.

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
7 0

Answer:

£216

Step-by-step explanation:

  • Cost = £6 per person
  • Teacher earns = 90% of total

<u>Total number of people:</u>

  • 13 + 11 + 16 = £40

<u>Total paymen</u>t:

  • 40*6= £240

<u>Teacher earns in total per given week:</u>

  • 240*90/100 = £216

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Find the mode of the following number of countries randomly selected travelers visited in the past two years. 13,13,15,7,8,4,4,7
Aliun [14]

Answer:

The mode of the following number of countries randomly selected travelers visited in the past two years is 13.

Step-by-step explanation:

The mode of a data-set is the value that appears the most commonly, the most frequently.

In this data-set:

13 appears 3 times

7 and 4 twice

The others once

So 13 is the mode.

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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The width of a rectangle is 22 inches and the perimeter is at least 165 inches. what inequality could be used to find the minimu
Lera25 [3.4K]
The answer is D.

We know that a rectangle has two widths that are equal and two lengths that are equal. One width is 22, so the other one is also 22.

If you wanted to find the lengths, you would add both widths together (same as multiplying a width by two) and add that to the two lengths equaled to the perimeter.

So, 22 * 2 + 2x = perimeter of rectangle. We added all four sides together.

We know that the perimeter is at least 165, so 22 * 2 + 2x = 165. Here's the twist. They want the most minimum possible length. So, what answer choice gives you 165 or less for the most minimum or smallest length while still getting to 165?
That is D.
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Hope this helped!
6 0
3 years ago
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iren [92.7K]

Answer:

21.33 to nearest hundredth

Step-by-step explanation:

Inverse Variation is y = k / x where k is a constant.

Plug in the given values to find k:-

16 = k/4

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So when x = 3,   y = 64/3 = = 21.33 to nearest hundredth.

6 0
4 years ago
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