All categories

3 years ago

Chris Evans drives 300 miles per week in his Honda Civic that gets 22 miles per gallon of gas. He

Mathematics

1 answer:

fenix001 [56]3 years ago

8 0

Answer:

old car $20,909
new car: $29,960

Step-by-step explanation:

At 300 miles per week, Chris drives 300×52 = 15,600 miles per year. His gas cost can be figured as ...

(5 years)×(miles per year)÷(miles/gallon)×($ per gallon) = $273,000/(miles per gallon)

a) old car cost = repair cost + gas cost + insurance cost

= 5($1200) + $273,000/22 + 5($500) ≈ $20,909 . . . over 5 years

b) new car cost = purchase cost + gas cost + insurance cost

= $20,000 + $273,000/50 +5($900) = $29,960 . . . over 5 years

You might be interested in

What is the area of a parallelogram with a base of 38 meters and a height of 12 meters?

8090 [49]

For this case we have by definition that the area of a parallelogram is given by:

$A = b * h$

Where:

b: It's the base

h: It's the height

According to the data we have:

$b = 38\ m\\h = 12 \ m$

Substituting in the formula:

$A = 38 * 12\\A = 456$

The area of the parallelogram is $A = 456 \ m ^ 2$

Answer:

$A = 456 \ m ^ 2$

4 0

3 years ago

Read 2 more answers

Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your

BaLLatris [955]

$f(x,y)=\dfrac{y^3}x$

a. The gradient is

$\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath$

$\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}$

b. The gradient at point P(1, 2) is

$\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}$

c. The derivative of $f$ at P in the direction of $\vec u$ is

$D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}$

It looks like

$\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath$

so that

$\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2$

Then

$D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}$

$\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}$

7 0

3 years ago

Which one is it?<br> A, B, C, or D?

grigory [225]

Answer: I'd go with C

Step-by-step explanation:

3 0

3 years ago

Which expression represents the product of 83 and x

anzhelika [568]

The product is the result of multiplication

so the product of 83 and x is : 83x

7 0

3 years ago

Read 2 more answers

Find a point-slope form for the line with slope 1 over 5 and passing through the point -8, -7

Whitepunk [10]

Answer:

(1/5)x-5.4=y

Step-by-step explanation:

mx+b=y

m=(1/5)

(-8,-7)=(x,y)

(1/5)(-8)+b=(-7)

-1.6+b=-7

b=-5.4

(1/5)x-5.4=y

6 0

3 years ago