Let's actually find the line of best fit...
m=(nΣyx-ΣyΣx)/(nΣx^2-ΣxΣx)
m=(11*836-130*55)/(11*385-3025)
m=2046/1210
m=93/55
b=(Σy-93Σx/55)/n
b=(55Σy-93Σx)/(55n)
b=(7150-5115)/(55*11)
b=185/55, so the line of best fit is:
y=(93x+185)/55
A) The approximate y-intercept (the value of y when x=0) is 185/55≈3.36.
Which means that those who do not practice at all will win about 3.36 times
B) y(13)=(93x+185)/55
y(13)≈25.34
So after 13 months of practice one would expect to win about 25.34 times.
Answer:
55.5 u^2
Step-by-step explanation:
Split the quadrilateral into 2 triangles. There are two ways to do this, but I'm only doing one of them.
On the 5-11 triangle, use the two of the lengths and plug them into the triangle area formula. (L x W)/2 = A
5-11 triangle area: 27.5
Do the same for the 7-8 triangle. Plug it into the same formula.
7-8 triangle area: 28
Add the two areas. 27.5 + 28 = 55.5
1) x³ + 2x² - x - 2 2) 2x³ + 5x² - 8x - 20 = 0
x²(x + 2) - (x + 2) x²(2x + 5) - 4(2x + 5) = 0
(x + 2)(x² - 1) (2x + 5)(x² - 4) = 0
(x + 2)(x - 1)(x + 1) x = -5/2, +-2
x = -2, 1, -1 << a is the answer.
hope that helps, God bless!
She would have to score atleast a 74 on the test for her average to be 78