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Mkey [24]
3 years ago
11

Seven times a number is equal to 12 more than three times the number. Find the number

Mathematics
1 answer:
nadya68 [22]3 years ago
5 0
x-\ number\\\\
7x=3x+12\ \ \ | subtract\ 3x\\\\
4x=12\ \ \ | divide\ by\ 4\\\\
x=3\\\\
Number\ is\ 3.
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PLEASE HURRY!50 POINTS ANS BRAILIEST
densk [106]

Answer:

A:

The decreasing value of car 1 can be represented by an exponential function and car 2 by a linear function

B:

Car 1: f(x) = 18500(0.94)^{x}

Car 2: f(x) = 18500 - 1000x

C:

Car 1 would be $10600.40 after 9 years

Car 2 would be $9500.00 after 9 years

There is a significant difference of $1100.40 in value.

Step-by-step explanation:

f(x) = ar^{x}\\f(0) = a = 18500\\f(x) = 18500r^{x}\\f(1) = 18500r = 17390\\r = \frac{17390}{18500} = 0.94\\f(x) = 18500(0.94)^{x}

7 0
4 years ago
Which rate is the lowest price? <br> $6.30 for 9 <br> $5.50 for 5 <br> $4.20 for 7 <br> $0.80 each
Sedbober [7]
Answer: $4.20 for 7
This problem can be solved by dividing the pay by the number of items.

$6.30 / 9 = $0.70
$5.50 / 5 = $1.10
$4.20 / 7 = $0.60
$0.80 / 1 = $0.80

This shows that for the third option, $4.20 for 7, the rate per item is the lowest.
7 0
4 years ago
Which of the following statements is not​ true? A. If the probability of an event occurring is​ 0, then it is impossible for tha
FromTheMoon [43]

Answer:

C. If the probability of an event occurring is​ 1.5, then it is certain that the event will occur.

Step-by-step explanation:

Probability is a value between <em>0 and 1</em> (including both values). Thus, to say that there is a probability of 1.5 is not correct, and, therefore, this statement is not true.

We can rewrite the statement as "If the probability of an event occurring is 1, then it is completely certain that the event will occur."

Statement A.

Suppose the event is A. Then, if P(A) = 0, it is completely certain that the event will not occur. It is true.

Statement B.

\\ if P(A) = 0\;then\;P(\overline{A}) = 1 - 0 = 1. Then, the statement is true.

Statement C.

We already explained the <em>statement C is not true</em> because the values for probabilities are between 0 and 1 (including both values). A probability of 1.5 is meaningless as a result.

Statement D.

For the same reason explained in C, the probability can never be a negative value. So, this statement is also true.  

4 0
3 years ago
Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th
DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that A \cap B = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

A + (A \cap B) = 0.40

A + 0.17 = 0.40

A = 0.23

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

B + (A \cap B) = 0.35

B + 0.17 = 0.35

B = 0.18

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

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