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trapecia [35]
3 years ago
8

Person A sold his bicycle to Person B at a profit of 50 %.

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
4 0

Answer:

$147.46

Step-by-step explanation:

CP= x

SP= x+ 50%= 1.5x

1.5x- 4%= 230.40

1.5x*0.96= 230.4

x= 230.4/1.5*0.96

x= 147.456 ≈ $147.46

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An apple tree is 93 ft tall and a peach tree is 5ft tall. How much taller is the
dmitriy555 [2]
88ft. You need to subtract 5 from 93 (93-5) which would equal 88
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Find the length indicated<br> Find SR (image)
uranmaximum [27]

Answer:

SR = 5

Step-by-step explanation:

We know that the two lines are equal to each other and thus TS + SR = 13

So, we can simply set the two equations of the first line equal to 13:

x + 2 + 2x - 7 = 13

3x - 5 = 13

3x = 18

x = 6

Now we plug in 6 for x in the SR equation:

2 * 6 = 12 - 7 = 5

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2 years ago
can someone help with this please! tell what number each symbol is equivalent to and be sure to show how to answer it, i will gi
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Answer:

1

Step-by-step explanation:

6 0
3 years ago
A house painter decides how many cans of paint to buy based on the total surface area of the house. The table below shows the su
makvit [3.9K]

Answer:

There is no image

Step-by-step explanation:

7 0
3 years ago
You do a study of hypnotherapy to determine how effective it is in increasing the number of hours of sleep subjects get each nig
brilliants [131]

Answer:

Confidence interval

8.98-2.2\frac{1.29}{\sqrt{12}}=8.16    

8.98+2.2\frac{1.29}{\sqrt{12}}=9.80  

And the margin of error would be:

ME=2.2\frac{1.29}{\sqrt{12}}=0.819

Step-by-step explanation:

For this case we have the followig dataset:

DATA: 8.2; 9.1; 7.7; 8.6; 6.9; 11.2; 10.1; 9.9; 8.9; 9.2; 7.5; 10.5

We can calculate the mean and the deviation with the following formulas:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

\bar X= 8.98[/tex[tex]s = 1.29

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=12-1=11

The Confidence level is 0.95 or 95%, the value of significance is \alpha=0.05 and \alpha/2 =0.025, and the critical value would be t_{\alpha/2}=2.20

Repplacing the info we got:

8.98-2.2\frac{1.29}{\sqrt{12}}=8.16    

8.98+2.2\frac{1.29}{\sqrt{12}}=9.80    And the margin of error would be:

ME=2.2\frac{1.29}{\sqrt{12}}=0.819

7 0
3 years ago
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