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nikitadnepr [17]
4 years ago
12

What is the solution to this equation? X-14=-9

Mathematics
2 answers:
Reil [10]4 years ago
7 0

5 - 14 = -9, therefore x = 5.

Hope this helps!

Yanka [14]4 years ago
7 0

Simplifying

x + -14 = -9

Reorder the terms:

-14 + x = -9

Solving

-14 + x = -9

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '14' to each side of the equation.

-14 + 14 + x = -9 + 14

Combine like terms: -14 + 14 = 0

0 + x = -9 + 14

x = -9 + 14

Combine like terms: -9 + 14 = 5

x = 5

Simplifying

x = 5

hope this helps!

((:

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<h3>What is the Euler's Formula?</h3>

The Euler's formula is given as,  F + V = E + 2, where:

  • F = number of faces (number of regions)
  • V = vertices
  • E = number of edges (number of segments).

Given that the pentagonal prism has the following dimensions:

  • F = 7
  • V = 10
  • E = number of segments = ?

Plug in the values into the Euler's formula, F + V = E + 2:

7 + 10 = E + 2

17 - 2 = E

E = 15

Therefore, using the Euler's formula, the number of segments in the pentagonal prism is: 15.

Learn more about the Euler's formula on:

brainly.com/question/1178790

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Answer:

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Step-by-step explanation:

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  f(x) ⇒ f(x -h) . . . . translation right h units

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  f(x) ⇒ k·f(x) . . . . . vertical scaling by a factor of k; reflection over x-axis when k < 0

  f(x) ⇒ f(x/k) . . . . . horizontal scaling by a factor of k; reflection over y-axis when k < 0

In the above, "scaling" will be expansion when |k| > 1, compression when |k| < 1.

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Your transformation is ...

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<em>Additional comment</em>

Like much of math, it is all about matching patterns.

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\qquad\qquad\huge\underline{{\sf Answer}}

Both the given lines in graph intersect at point (5 , -2), the point must satisfy both the equations.

and if we check the options, we will observe that D. option has both the equations that satisfy the given conditions.

that is ~

\qquad \sf  \dashrightarrow \: x + y = 3

put y = - 2,we will get :

\qquad \sf  \dashrightarrow \: x - 2 = 3

\qquad \sf  \dashrightarrow \: x = 5

so, 1st equation satifys the condition. let's check out 2nd one.

\qquad \sf  \dashrightarrow \: x + 2y = 1

put y = -2

\qquad \sf  \dashrightarrow \: x + (2 \times  - 2) = 1

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Answer:

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The greatest length of time Jeremy can rent the jet ski is 5 and Jeremy can rent maximum of 135 minutes.

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Assuming the number of additional 15-minutes increment be "x"

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⇒x\leq \frac{50}{10}

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A. 16 is divisible by 2 but not divisible by 3
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Answer: D, 36 supports the given conjecture.
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4 years ago
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