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Natalka [10]
3 years ago
14

Adult tickets to a basketball game cost $5. Student tickets cost $1. A total of $3,159 was collected on the sale of 1,339 ticket

s. How many of each type of ticket were sold?
Mathematics
1 answer:
ivolga24 [154]3 years ago
5 0

Answer:

  • 455 adult tickets
  • 884 student tickets

Step-by-step explanation:

Let "a" represent the number of adult tickets sold. Then 1339-a is the number of student tickets sold. The revenue collected was ...

  5a + 1(1339-a) = 3159

  4a = 1820 . . . . . . subtract 1339, collect terms

  a = 455 . . . . . . . . divide by 4; adult tickets sold

  (1339-a) = 884 . . . . student tickets sold

455 adult tickets and 884 student tickets were sold.

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Find an explicit formula for the arithmetic sequence -11, -3, 5, 13, ....
Alekssandra [29.7K]

Answer:

<u>b(n) = -11 + (n-1)*8</u>

<u></u>

Step-by-step explanation:

Let n be the sequence number, with n=1 the first number b(1) -11

The sequence changes by +8 each step.

<u><em>b(1)</em></u><em>   -11</em>         + 8 =   -3

<u><em>b(2)</em></u><em>   -3</em>          + 8 =    5

<u><em>b(3)</em></u>   <em> 5 </em>         + 8 =   13

<u><em>b(4)</em></u><em> </em> <em>13</em>

b(1) = -11

b(2) = -3.   or b(1) + 1*8

b(3) =  5,    or b(1) + 2*8

b(4) =  13,   or b(1) + 3*8

We note that each step adds a multiple of 8 to the initial value of -11.  This can be stated as (n-1)*8

The formula for this sequence would be b(n) = b(1) + (n-1)*8

<u>b(n) = -11 + (n-1)*8</u>

Check:  Does n=3 return the value of 5?

b(n) = -11 + (n-1)*8

b(3) = -11 + ((3)-1)*8

b(3) = -11 + (2)*8

b(3) = -11 + 16

b(3) = 5   <u><em>YES</em></u>

5 0
2 years ago
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