Question

Log3+logx-log(x+1)=log2

Answer 1

Answer:

• x = 2

Step-by-step explanation:

These are the properties of logarithms that you have to use to solve the equation:

$logA+logB=log (AB)\\ \\ logA-logB=log(\frac{A}{B} )$

$logA=logB$⇒$A=B$

With that you can follow these steps and find the value of x:

$log3+logx-log(x+1)=log2\\ \\\\ log\frac{3x}{x+1} =log2\\ \\ \\ \frac{3x}{x+1} =2\\ \\ \\ 3x=2(x+1)\\ \\ \\ 3x=2x+2\\ \\ \\ x=2$