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3 years ago

7

Log3+logx-log(x+1)=log2

1 answer:

OlgaM077 [116]3 years ago

8 0

Answer:

x = 2

Step-by-step explanation:

These are the properties of logarithms that you have to use to solve the equation:

$logA+logB=log (AB)\\ \\ logA-logB=log(\frac{A}{B} )$

$logA=logB$ ⇒ $A=B$

With that you can follow these steps and find the value of x:

$log3+logx-log(x+1)=log2\\ \\\\ log\frac{3x}{x+1} =log2\\ \\ \\ \frac{3x}{x+1} =2\\ \\ \\ 3x=2(x+1)\\ \\ \\ 3x=2x+2\\ \\ \\ x=2$

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3 years ago

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taurus [48]

Answer:

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Step-by-step explanation:

we have

$-2x+2y+3z=0$ ----> equation A

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adds equation A and equation C

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adds equation B and equation C

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$2y+4z=2$ -----> equation E

we have the system

$5y+6z=5$ -----> equation D

$2y+4z=2$ -----> equation E

Multiply equation E by -1.5 both sides

$-1.5(2y+4z)=-1.5(2)$

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adds equation D and equation F

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substitute the value of y in equation E (or substitute in equation D)

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$2+4z=2$

$4z=0$

$z=0$

<em>Find the value of x</em>

substitute the value of y and z in equation A (or equation B or C)

$-2x+2(1)+3(0)=0$

$-2x+2=0$

$-2x=-2$

$x=1$

therefore

The solution of the system of equations is

$x=1, y=1, z=0$

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