150 = 12
150 +150 = 300 which = 24
150 + 150 + 150 = 450 which =36
the remaining 50 is 12 ÷ 3, so 4. 36 + 4 = 40.
therefore, 40 L of gasoline are needed to go 500km
Combine like terms.
7g + 4g + 3g + g = 15g
15g - 13g = 2g
2g = 10
Divide by 2 on both sides.
g = 5
Answer:
I think jillian will have to run 10 miles
Step-by-step explanation:
2 miles = 100 calories
in order to burn 500 calories
2 miles = 100 calories burned
4 miles = 200 calories burned
6 miles = 300 calories burned
8 miles = 400 calories burned
10 miles = 500 calories burned
Using a system of equations, it is found that since 20 child bikes and 6 adult bikes would require more testing than the allocated time, it is not possible to build this amount.
<h3>What is a system of equations?</h3>
A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In this problem, the variables are:
- Variable c: number of child bikes.
- Variable a: number of adult bikes.
Each child bike requires 4 hours to build, as do each adult bike. The company has 100 hours of testing, hence:
4c + 4a = 100.
c + a = 25.
With 20 child bikes and 6 adult bikes in a week, we have that c = 20, a = 26, hence:
c + a = 26
20 child bikes and 6 adult bikes would require more testing than the allocated time, it is not possible to build this amount.
More can be learned about a system of equations at brainly.com/question/24342899
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10/10 in 1 whole and 1/100 in one whole