Answer:
42
Step-by-step explanation:
<h2>Perimeter of quadrilateral with inscribed circle:</h2>
Two tangents from a point outside the circle to some point to a circle are of equal lengths.
CB = 3+ 5 = 8
CD = 3+ 4 = 7
DA = 4 + 9 = 13
AB = 9+ 5 = 14
Perimeter = 8 + 7 + 13 + 14
= 42
Option 4 is correct i.e. <span>The volume of the box is increasing at a rate of 192 cm^3/min.
</span>Given : Volume of the rectangular box = x²h
where x is edge and h is height.
The edge and the height are varying with time, therefore, we write,x = x(t)
h = h(t)
dh/dt = -3 and we shall calculate when x = 4, dx/dt = 2 and when h=15
V = x²h dV/dt = (2x × dx/dt × h) + (x² × dh/dt) dV/dt = 2×4×2×15 + (4)^2 ×(-3) dV/dt = 240 - 48
dV/dt = 192
Because dV/dt is positive, hence the volume is increasing
Answer:
it would be a............ .
2/12 chance, or as a reduced fraction, 1/6