Answer:
Wow everyone is being so noice today is today some kind of special occassion?
5 miles high is one of the sides of a triangle depending on accuracy level
h^2=x^2+y^2
we don't have 2 distances
Tan A=O/a
O=a tan A
We solve for O because the angle is at the top of the line going up and we want the opposite angle that is along the ground
O=5×tan(173.7/2)=90.854033512
The distance he can see is:
90.85*2~181.7 miles
Now we need to find the distance between lines:
The north south distance between each line is 69 miles
thus the number of degrees he will see will be:
181.7/69
=2 19/30
Answer:
ΔABD ≅ ΔACD by SAS, therefore;
by CPCTC
Step-by-step explanation:
The two column proof is presented as follows;
Statement
Reason
ABCD is a trapezoid
Given
Given
Definition of a trapezoid
ABCD is an isosceles trapezoid
Left and right leg are equal
∠BAD ≅ ∠CDA
Base angle of an isosceles trapezoid are congruent
Reflexive property
ΔABD ≅ ΔACD
By SAS rule of congruency
CPCTC
CPCTC; Congruent Parts of Congruent Triangles are Congruent
SAS; Side Angle Side rule of congruency
X^2 - x = 7
(x - 0.5)^2 - 0.25 = 7
(x - 0.5)^2 = 7.25
(x - 0.5) = +/- sqrt 7.25
x = 0.5 +/- sqrt7.25
solution set is {-2.19, 3.19,}