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Oksi-84 [34.3K]
3 years ago
11

R^4/9 translated verbal expression

Mathematics
1 answer:
Verizon [17]3 years ago
3 0

Answer:

The quotient of 4 and 9 raised to the power of r.

Step-by-step explanation:

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100x²7<br> Quadratic equation
grin007 [14]
Hope the answer I gave you helps!!!
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3 years ago
What is the slope of the line passing through the points (1, 2) and (5, 4)?​
bulgar [2K]
<h2>SOLVING</h2>

\Large\maltese\underline{\textsf{A. What is Asked}}

What is the slope of the line passing through the point (1,2) and (5,4)

\Large\maltese\underline{\textsf{This problem has been solved!}}

Formula used, here  \bf{\dfrac{y2-y1}{x2-x1}

_______________________________________________________

\bf{\dfrac{4-2}{5-1} | simplify

\bf{\dfrac{2}{4} | reduce

\bf{\dfrac{1}{2}

\rule{300}{1.7}

\bf{Result:}

         \bf{=Slope:\dfrac{1}{2}

\boxed{\bf{aesthetic\not101}}

3 0
2 years ago
Read 2 more answers
B) Alfredo said that Angle 7 and Angle 6 are congruent and that would prove Line m
malfutka [58]

Answer:

Yes if Angle 7 and angle 6 are linear pairs in angles created by a straight line that cuts through parallel lines.

Step-by-step explanation:

Remember that two parallel lines that are cut by a transveral will create 8 angles, which will be similar to each other. Making four pairs of congruent angles means that they will be exactly the same angle located in different parts of the system. So if angles 6 and 7 are congruent, and the lines are cut by a transversal, then the lines are parallel.

6 0
3 years ago
Which expression is an equivalent expression of 12x + 10 + 4y?
galina1969 [7]

Is there an answer key?

4 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST!!(plz show work too)
trapecia [35]

\huge \bf༆ Answer ༄

Let the capacity of bus be x students

And van be y students, now ;

From the given statements we get two equations ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \:   \:  \:  \: \:  (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:13x + 5y = 670 \:  \:  \:  \:  \: (2)

multiply the equation (2) with 2 [ it won't change the values ]

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \: \:  \:  \:   \:  \:  \:  \:  \: (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y = 1340 \:  \:  \:  \:  \: (3)

Now, deduct equation (1) from equation (3)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y - 2x - 10y = 1340 - 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:24x = 1080

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 1080 \div 24

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 45

Therefore each bus can carry (x) = 45 students

Now, plug the value of x in equation (1) to find y ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(2 \times 45) + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:90 + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 260 - 90

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 170

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 170 \div 10

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 17

Hence, each van can carry (y) = 17 students in total.

5 0
2 years ago
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