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hjlf
3 years ago
6

7 less than 14 times a number

Mathematics
1 answer:
Debora [2.8K]3 years ago
4 0

Answer:

14x-7

Step-by-step explanation:

14x-7

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Please help me solve this problem.
Tasya [4]

Let

x-------> total peanuts originally from the bag

we know that

1) Phillip took 1/3 of the peanuts from the bag--------> (1/3)*x

remaining=x-(1/3)*x-------> (2/3)*x

2) Joy took 1/4 of the remaining peanuts-------> (1/4)*[(2/3)*x]----> (1/6)*x

remaining= (2/3)*x-(1/6)*x------> (1/2)*x

3) Brett took 1/2 of the remaining peanuts------> (1/2)*(1/2)*x-----> (1/4)*x

remaining= (1/2)*x-(1/4)*x-------> (1/4)*x

4) Preston took 10 peanuts------> 10

(1/4)*x-10=71----> multiply by 4 both sides----> x-40=284----> x=324 peanuts

5) Total originally peanuts from the bag is equal to 324 peanuts

6) Phillip took (1/3)*x-----> (1/3)*324=108 peanuts

7) Joy took (1/6)*x------> (1/6)*324=54 peanuts

8) Brett took (1/4)*x------> (1/4)*324=81 peanuts

9) Preston took 10

so

check

108+54+81+10=253

remaining=324-253------> remaining=71-------> is correct

6 0
4 years ago
Hector can fit 75 compact discs into 5 boxes. How many compact discs can he fit into 14 boxes?
Karolina [17]

Answer:

Hector can fit 210 compact discs into 14 boxes.

8 0
3 years ago
What do i do for this problem
Margaret [11]
<span>The answer would be 20.

The question is asking you to find the value of the expression for when c = 100, so we have to put 100 where c is in the equation. Given that fact, we start with c/5, then put the 100 in for c.
c/5 = ??
100/5 = 20. </span>
4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%20%5Csf%20%5Chuge%7B%20question%20%5Chookleftarrow%7D" id="TexFormula1" title=" \sf \huge
BabaBlast [244]

\underline{\bf{Given \:equation:-}}

\\ \sf{:}\dashrightarrow ax^2+by+c=0

\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.

\sf We\:know,

\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}

\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}

\underline{\large{\bf Identities\:used:-}}

\boxed{\sf (a+b)^2=a^2+2ab+b^2}

\boxed{\sf (√a)^2=a}

\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}

\boxed{\sf \sqrt{\sqrt{a}}=a}

\underline{\bf Final\: Solution:-}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}

\bull\sf Apply\: Squares

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}

\bull\sf Put\:values

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}

\bull\sf Simplify

\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}

\underline{\bf More\: simplification:-}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}

\underline{\Large{\bf Simplified\: Answer:-}}

\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}

5 0
2 years ago
Read 2 more answers
879,100 rounded to the nearest ten thousand
faust18 [17]
880,000 is the answer
5 0
3 years ago
Read 2 more answers
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