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3 years ago

Find the value of x in the isosceles triangle shown below.

Mathematics

1 answer:

joja [24]3 years ago

7 0

Answer: C. 10

Explanation:

Take half right triangle from the isosceles triangle:

We get side lengths:

12/2 = 6, 8, and x

And use Pythagorean’s theorem to find x:

6^2 + 8^2 = x^2
36 + 64 = x^2
100 = x^2
10 = x

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Feliz [49]

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4 0

3 years ago

Find compound interest on12600rupees for 2years at10% per annum compounded anually<br>

vekshin1

Answer:

₹2520

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 10%/100 = 0.1 per year,

then, solving our equation

I = 12600 × 0.1 × 2 = 2520

I = ₹ 2,520.00

The simple interest accumulated

on a principal of ₹ 12,600.00

at a rate of 10% per year

for 2 years is ₹ 2,520.00.

3 0

3 years ago

The price of a book rises from £16 to £20 work out the percentage increase

Vladimir79 [104]

Answer:

25%

Step-by-step explanation:

20-16=4

16…4

1 … 4/16

100…4/16×100

1/4×100

25%

5 0

3 years ago

Calculate f(x) for the given domain values.

Maksim231197 [3]

Answer:

See explanation

Step-by-step explanation:

1. The given function is

$f(x) = - 3x$

The domain values are: x=0, 2, -1, 4, -2

When x=0

$f(0) = - 3 \times 0 = 0$

When x=2,

$f(x) = - 3 \times 2 = - 6$

When x=-1

$f(x) = - 3 \times - 1 = 3$

When x=4

$f(4) = - 3 \times 4 = - 12$

When x=-2

$f( - 2) = - 3 \times - 2 = 6$

2. The given function is

$f(x) = \frac{1}{3} x$

When x=3,

$f(3) = \frac{1}{3} \times 3 = 1$

Similarly,

$f( - 3) = \frac{1}{3} \times - 3 = - 1$

$f(300) = \frac{1}{3} \times 300 = 100$

$f( - 180) = \frac{1}{3} \times - 180 = - 60$

$f(99) = \frac{1}{3} \times 99 = 33$

8 0

3 years ago

Suppose that f(x) is the (continuous) probability density function for heights of American men, in inches, and suppose that f(69

anastassius [24]

Answer:

(a) 7.6%

(b) 46.2% 42.4%

Step-by-step explanation:

(a)According to the definition of Continuous probability distribution

$f(x) = \frac{d}{dx}F(x)$

$f(x) = \frac{F(x + h) - F(x - h)}{(x + h) - (x - h)}$

$f(69) = \frac{F(69 + 0.2) - F(69 - 0.2)}{0.4}$

⇒ 0.19 × 0.4 = F(69.2) - F(68.8)

⇒ F(69.2) - F(68.8) = 0.076

⇒ 7.6%

(b) Given F(69) = 0.5

$f(x) = \frac{d}{dx}F(x)$

$f(x) = \frac{F(x) - F(x - h)}{x - (x - h)}$

$f(69) = \frac{F(69) - F(69 - 0.2)}{0.2}$

⇒ 0.19 × 0.2 = F(69) - F(68.8)

⇒ F(68.8) = 0.5 - 0.038 = 0.462

⇒ 46.2%

$f(x) = \frac{d}{dx}F(x)$

$f(x) = \frac{F(x) - F(x - h)}{x - (x - h)}$

$f(69) = \frac{F(69) - F(69 - 0.4)}{0.4}$

⇒ 0.19 × 0.4 = F(69) - F(68.8)

⇒ F(68.8) = 0.5 - 0.076 = 0.424

⇒ 42.4%

5 0

3 years ago