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3 years ago

Change the improper fraction to a mixed number. 30/7

Mathematics

2 answers:

serg [7]3 years ago

8 0

The answer would be four and two over seven or 4 2/7

julsineya [31]3 years ago

7 0

The answer would be four and two over seven or 4 2/7

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WHAT IS S=2PIR^2+2PIRH SOLVE FOR H

grigory [225]

$\\~\qquad\quad S\ =\ 2PIR^2+2PIRH\\\underline{-2PIR^2\qquad-2PIR^2\qquad\quad\ }\\\\ S-2PIR^2=2PIRH\\\\ 2PIRH\ =\ S-2PIR^2\\\underline{ :(2PIR)\qquad :(2PIR)}\\\\\\ H=\dfrac{S-2PIR^2}{2PIR}\\\\\\ H=\dfrac{S}{2PIR}-\dfrac{2PIR^2}{2PIR}\\\\\\ H=\dfrac{S}{2PIR}-R$

or:

$\\~\qquad\quad S\ =\ 2PIR^2+2PIRH\\\\~\qquad\quad S\ =\ 2PIR(R+H)\\\underline{:(2PIR)\qquad :(2PIR)}\\\\\\~\ \ \dfrac{S}{2PIR}\ =\ R+H\\\\\\ \dfrac{S}{2PIR}-R=H\\\\\\ H=\dfrac{S}{2PIR}-R$

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4 years ago

(Use the formula SA=6s2 , where SA is the surface area and s is the edge length of the cube, to solve this problem.) Gavan must

11Alexandr11 [23.1K]

I believe the answer is 3/8, if i'm wrong then i really sorry

6 0

3 years ago

9y-15x= -36 in slope intercept form

nataly862011 [7]

It would be y=5/3 x-5

8 0

3 years ago

Read 2 more answers

A 40 of foxes in a wildlife preserve quadruples in size every 13 years. The function y=40•4^4, where x is the number of 13-year

SashulF [63]

Answer:

640 foxes

Step-by-step explanation:

The actual formula is $y = 40 * 4^{x}$

Now that we have the real formula we would need to find out how many 13 year periods exist in the 26 years that are being used in the question. We calculate this by simply dividing 26 by 13.

26 / 13 = 2 periods

Therefore, now that we know there are 2 periods of 13 years in the 26-year span, we plug this value into the formula and solve for y...

$y = 40 * 4^{x}$

$y = 40 * 4^{2}$

$y = 40 * 16$

$y = 640$

Finally, we can see that there should be 640 foxes after 26 years.

7 0

3 years ago

Drag the correct graph to the box under the equation it corresponds to.<br><br> HELP YOU GUYS

ra1l [238]

Answer:

<h2>See below</h2>

Step-by-step explanation:

I can't drag and drop the graphs, but I can graph the equations shown. Then, all you will have to do is match the graphs shown the the graph that I will provide.

<h3>EQUATION 1: y = x² - 2</h3>

Graph Properties:

Opens up

Vertex is 0, -2

Axis of symmetry is x = 0

Graph photo shown in file called equation 1 graph

<h3>EQUATION 2: y = 2x²</h3>

Graph Properties:

Opens up

Vertex is 0, 0

Axis of symmetry is x = 0

Graph photo shown in file called equation 2 graph

<h3>EQUATION 3: y = (x - 2)²</h3>

Graph Properties:

Opens up

Vertex is 2, 0

Axis of symmetry is x = 2

Graph photo shown in file called equation 3 graph

I'm always happy to help :)

5 0

3 years ago