Question

the length of one of the diagonals of a quadrilateral is 10 cm and the particular drawn from the opposite vertices to this diagonal are the are of length 2.8 cm and 4.2 cm find the area of the quadrilateral

Answer 1

Answer:

Therefore the area of the quadrilateral =35 cm²

Step-by-step explanation:

Given, the length of one of diagonal of quadrilateral is 10 cm and perpendicular drawn from the opposite vertices to this diagonal are the length of 2.8 cm and 4.2 cm.

A diagonal divided a quadrilateral into two triangle.

Therefore the area of the quadrilateral

= sum of the area of the triangles

$=(\frac{1}{2}\times 10\times 2.8+ \frac{1}{2}\times 10\times 4.2)$cm²      [ area of a triangle$= \frac{1}{2}\times base\times height$]

=35 cm²