Seventy-nine-thousand-and-thirty-one
I hope that's right I'm not too sure lol
Using the concept of domain, the domain of (f.g)(x) is given by:
{x ∈ ℝ | x ≠ 3}
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- The domain of a function is given by all possible input values, that is, <u>on a graph, all values that the x-axis assumes.</u>
- In the graph, <u>function f assumes all real values.</u>
- Function g is not defined for x = 3, thus, it's domain is all real values except 3.
- Thus, the multiplication, as
, will also not be defined at x = 3, and the domain of the multiplication is:
{x ∈ ℝ | x ≠ 3}
A similar problem is given at brainly.com/question/4175434
Answer:70
Step-by-step explanation:910/13=70 so he gives away 70 loafs of bread.
<span>Given the diagram, where AB and EF are horizontal lines and CB is a vertical line segment.
Given that FB : FC = 4 : 3,
From the diagram, the coordinate of A is (-10, -8) and the coordinate of C is (-3. -1).
We can also see that the coordinate of B is (-3, -8) (since CB is a vertical line means that B is the same x-value as C and AB is a horizontal line means that B is the same y-value as A)
Recall that the coordinate of a point dividing a line segment in the ratio m:n is given by (x1 + m/(m+n) (x2 - x1), y1 + m/(m+n) (y2 - y1))
Thus, since FB : FC = 4 : 3, this means that point F divides the line segment BC in the ratio 4 : 3.
Thus, the coordinate of F is given by (-3 + 4/(4+3) (-3 - (-3)), -8 + 4/(4+3) (-1 - (-8))) = (-3 + 4/7 (0), -8 + 4/7 (7)) = (-3, -4).
Also, given that FB : FC = 4 : 3, this means that point D divides the line segment AC in the ratio 4 : 3.
Thus, the coordinate of D is given by (-10 + 4/(4+3) (-3 - (-10)), -8 + 4/(4+3) (-1 - (-8))) = (-10 + 4/7 (7), -8 + 4/7 (7)) = (-6, -4).
Therefore, the coordinates of point D is (-6, -4).</span>
Answer:
they cost 13.86666666666667
Step-by-step explanation:
