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julia-pushkina [17]
3 years ago
8

Given that P(BA) means the probability of event B occurring given that event A will occur or has occurred, which of the followin

g correctly calculates this probability?
A) P(B)
B) P(A and B)/P(B)
C) P(A)/P(B)
D) P(A and B)/P(A)​
Mathematics
2 answers:
Westkost [7]3 years ago
3 0
The correct answer is D
sasho [114]3 years ago
3 0

Answer:

D

Step-by-step explanation:

the answer is d because b and a have to happen at the same time

You might be interested in
If T equals 1 / r + 1 / s equals r + S over RS, then what is 1 / T in terms of R&S?
Thepotemich [5.8K]
T=\dfrac{1}{r}+\dfrac{1}{s}\\\\T=\dfrac{1\cdot s}{r\cdor s}+\dfrac{1\cdot r}{r\cdot s}\\\\T=\dfrac{s}{rs}+\dfrac{r}{rs}\\\\T=\dfrac{s+r}{rs}\to\dfrac{1}{T}=\dfrac{rs}{s+r}
7 0
4 years ago
Quadrilateral BECK is known to be a rhombus. Two of the vertices are B(3,5) and C(7,-3).
Zanzabum

Answer:

a. The slope of EK is \frac{1}{2}

b. The equation of line EK is y = \frac{1}{2} x -  \frac{3}{2}

Step-by-step explanation:

The form of the equation of a line is y = m x + b, where

  • m is the slope of the line
  • b is the y-intercept

The rule of the slope is m = \frac{y2-y1}{x2-x1} , where

  • (x1, y1) and (x2, y2) are two points on the line
  • The rule of the mid-point is (\frac{x1+x2}{2},\frac{y1+y2}{2})

∵ BECK is a rhombus

∵ The diagonal is the line that joins two opposite vertices

∵ B and C are opposite vertices in the rhombus

∵ E and K are opposite vertices in the rhombus

∴ BC and EK are the diagonals of the rhombus BECK

∵ The diagonals of the rhombus are ⊥ and bisect each other

∴ EK is ⊥ bisector to BC

→ Let us find the slope and the mid-point of BC

∵ B = (3, 5) and C = (7, -3)

∴ x1 = 3 and y1 = 5

∴ x2 = 7 and y2 = -3

→ Substitute them in the rule of the slope above to find it

∵ m = \frac{-3-5}{7-3} = \frac{-8}{4} = -2

∴ m = -2

∴ The slope of BC = -2

→ To find the slope of EK reciprocal the slope of BC and change its sign

∴ m⊥ = \frac{1}{2}

∴ The slope of EK = \frac{1}{2}

a. The slope of EK is \frac{1}{2}

→ Substitute the value of the slope in the form of the equation above

∵ y = \frac{1}{2} x + b

→ To find b substitute x and y in the equation by the coordinates

   of a point on the line

∵ The mid-point of BC is the mid-point of EK

∵ The mid-point of BC = (\frac{3+7}{2},\frac{5+-3}{2}) = (\frac{10}{2},\frac{2}{2}) = (5, 1)

∴ The mid-point of EK = (5, 1)

→ Substitute x by 5 and y by 2 in the equation

∵ 1 =  \frac{1}{2}(5) + b

∴ 1 =  \frac{5}{2} + b

→ Subtract  \frac{5}{2} from both sides

∴  -\frac{3}{2} = b

→ Substitute the value of b in the equation

∵ y = \frac{1}{2} x + -\frac{3}{2}

∴ y = \frac{1}{2} x -  \frac{3}{2}

b. The equation of line EK is y = \frac{1}{2} x -  \frac{3}{2}

6 0
3 years ago
Which value is the solution for this equation<br><br>2/3(6h-9)=6<br>A) -1<br>B) 1<br>C) 3<br>D) 5
faust18 [17]

Answer:

h = 3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

2/3(6h - 9) = 6

<u>Step 2: Solve for </u><em><u>h</u></em>

  1. [Division Property of Equality] Divide 2/3 on both sides:                             6h - 9 = 9
  2. [Addition Property of Equality] Add 9 on both sides:                                   6h = 18
  3. [Division Property of Equality] Divide 6 on both sides:                                h = 3
8 0
3 years ago
I need help with this <br>​
-BARSIC- [3]

Answer:

Step-by-step explanation:

3 + 6 * 4 - 80 / 10 + 4 - 18 = 3 + 24 - 8 + 4 - 18 = 27 - 8 + 4 - 18 = 19 + 4 -18 = 23 - 18 = 5

6 0
3 years ago
Read 2 more answers
solve 5x^2-7x+2=0 completing the square. what is the constant added on to form the perfect square trinomial
kenny6666 [7]
Best to factor 5 out of the first 2 terms:

5x^2-7x+2=0  =>  <span>5(x^2 - [7/5]x)                          +2=0

Take half of [-7/5]:  That'd be -7/10.

Square 7/10, add it to  </span>5(x^2 - [7/5]x)                          +2=0  and then subtract it:


5(x^2 - [7/5]x)+ 49/100       -  49/100       )                  +2=0

Then we have   5(x- [7/10] )^2 - 49/100 ) + 200/100 = 0

                          5(x-7/5)^2  - 245/100 + 200/100 = 0
                           5(x-7/5)^2 - 45/100 = 0
Dividing all terms by 5,  x-7/5 = plus or minus sqrt( 9/100 )
                                       x-7/5 = plus or minus 3/10

Then one root is x = 7/5 + 3/10, or  x= 17/10  (answer #1)

The other is        x = 7/5 - 3/10, or x = 14/10 - 3/10, or x = 7/10  (answer #2) 
3 0
3 years ago
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