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loris [4]
3 years ago
13

Help plss

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
3 0

Answer:

9 minutes

Step-by-step explanation:

you have to do 15% of 1 hour=0.15 times 60 which equals 9

Nookie1986 [14]3 years ago
3 0
Here for the points sorry:(
Ndndjd
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Need an answer thanks
MatroZZZ [7]

Answer:

CE = 105

Step-by-step explanation:

CE = CD + DE , hence

6x = 4x + 8 + 27 ( subtract 4x from both sides )

2x = 35 ( divide both sides by 2 )

x = 17.5

⇒ CE = 6 × 17.5 = 105



5 0
3 years ago
What is the radius of a circle with circumference 22 m?
Veseljchak [2.6K]

Answer:

3.5 cm

Step-by-step explanation:

Using the formula

c=2πr

r =C/2π = 22/2×π ≈ 3.50141cm

6 0
3 years ago
Read 2 more answers
Find the perimeter of a square with side a. Are the perimeter of the square and the length of its side directly proportional qua
erik [133]

Answer:

The perimeter is 8 cm.

Yes, the perimeter of a square is directly proportional to its side length.

Step-by-step explanation:

Given:

The side length of the square is, a=2\ cm

The perimeter of a square is the sum of all of its side lengths. The perimeter of a square of side length 'a' is given as:

P=a+a+a+a=4a

Plug in a=2\ cm and find perimeter, 'P'. This gives,

P=4\times 2=8\ cm

Therefore, the perimeter is 8 cm.

Now, two quantities are directly proportional only if their ratio is a constant.

Let us find the ratio of 'P' and 'a'.

We have, P=4a

Dividing both sides by 'a', we get:

\frac{P}{a}=\frac{4a}{a}\\\frac{P}{a}=4(Constant)

Therefore, the ratio of perimeter and side length is a constant. Hence, these are directly proportional quantities.

6 0
3 years ago
URGENT PLEASE HELP <br> please help me simplify this expression
Mandarinka [93]
I hope this helps you

3 0
4 years ago
If-2a &gt; 6, then<br> -a&gt;3<br> -a&lt;3<br> -a&lt;-3<br> -a&gt;-3
chubhunter [2.5K]

Answer:

a < - 3

Step-by-step explanation:

Given

- 2a > 6

Divide both sides by - 2, reversing the symbol as a result of dividing by a negative quantity, thus

a < - 3

5 0
3 years ago
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