Answer:It can be opened by most computers.
Explanation: it is a widely used file type that is able to be opend in a web browser if no PDF viewer app is instlled like Adobe.
Answer:
The answer is "Increased flexibility".
Explanation:
In the given question some information is missing that is the option of the question which can be described as follows:
A. Enhance scalability and efficiency
B. Enhance data security
C. Reducing data duplication
D. Increased flexibility
Flexibility is being used as an object for different types of applications. It is an engineering system which is that provides an easy way for all the scheme to respond to insecurity so, that its value is maintained or increased, It is also known as its key component, and certain option was incorrect, which can be described as follows:
- In option A, It is wrong because it is used in business data.
- In option B, It is wrong because it provides security.
- In option C, It removes duplicate data that's why it is wrong.
Answer: Believe in himself Despite the idea will good or bad
Explanation: We are humans, so he can make a mistake with his ideas, the most important thing for a positive workplace behaviors in the meetings is to show security about your thinking, your ideas also when you are talking, keep in mind that is normal the wrongs and the mistakes, but it is no final you can start again and do it better than the last time, and improve your behavior
The Scrum product owner is typically a project's key stakeholder.
This is key to successfully starting any agile software development project.
Answer:
Explanation:
The following is written in Java and prints out the pattern to and from the first num parameter that is passed to the function. Meaning it goes from num1 to 0 and then from 0 to num1 again. It prints all of the values in a single line seperated by a space and a test case was used using the values provided in the question. The output can be seen in the attached picture below.
static void printNumPattern(int n1,int n2){
System.out.print(n1 + " ");
if(n1<=0) {
return;
} else {
printNumPattern(n1-n2,n2);
}
System.out.print(n1 + " ");
}
