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Dimas [21]
3 years ago
12

Simplify the following expression.( Fraction form) 7-5/6 * 7-7/6

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
5 0

Answer:

1295/36

Step-by-step explanation:

the statement tell us:

(7-(5/6))*(7-(7/6))

we have:

(7-(5/6))=((6*7)-5)/6=(42-5)/6=37/6

and we have:

(7-(7/6))=((6*7)-7)/6=(42-7)/6=35/6

we need multiply both terms:

(37/6)*(35/6)=(37*35)/(6*6)

finally we have

1295/36

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The answer is D. Dilation. 
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how do you solve 2x-10=44+8× and -7x-2=24-9x and 27-11x=x-33 and 21x+6=17x-26 and 11x=8x-6 and -x-29=13+2x
balu736 [363]
2x-10=44+8x
subtract 2x from each side
8x-2x=6x
now we have -10=44+6x
subtract 44 from both sides
-10-44=-54
now we have -54=6x
divide both sides by 6
-54/6=-9
so x=-9
7 0
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A farmhouse shelters 11 goats and ducks.Altogether,there are 34 legs.How many of each animal are there?
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There are 4 ducks and 4.5 goats
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3 years ago
Calculus 2 Master needed, show steps with partial fraction decomposition <img src="https://tex.z-dn.net/?f=%5Cint%283x%5E2-26x%2
Vladimir79 [104]

Answer:

-ln|x−5| + 2 ln(x²+4) + 3 tan⁻¹(x/2) + C

Step-by-step explanation:

The fraction will be split into a sum of two other fractions.

The first fraction will have a denominator of x − 5.  The numerator will the a polynomial of one less order, in this case, a constant A.

The second fraction will have a denominator of x² + 4.  The numerator will be Bx + C.

\frac{3x^{2}-26x+26}{(x-5)(x^{2}+4)}=\frac{A}{x-5} +\frac{Bx+C}{x^{2}+4}

Combine the two fractions back into one using the common denominator.

\frac{A}{x-5} +\frac{Bx+C}{x^{2}+4}=\frac{A(x^{2}+4)+(Bx+C)(x-5)}{(x-5)(x^{2}+4)}

This numerator will equal the original numerator.

A(x^{2}+4)+(Bx+C)(x-5)=3x^{2}-26x+26\\Ax^{2}+4A+Bx^{2}-5Bx+Cx-5C=3x^{2}-26x+26\\(A+B)x^{2}+(C-5B)x+(4A-5C)=3x^{2}-26x+26

Match the coefficients.

A+B=3\\C-5B=-26\\4A-5C=26

Solve the system of equations.

A=-1\\B=4\\C=-6

So we can rewrite the integral as:

\int {(\frac{-1}{x-5}+\frac{4x-6}{x^{2}+4}) } \, dx

Solving:

\int {\frac{-1}{x-5}\, dx + \int {\frac{4x}{x^{2}+4}} \, dx - \int {\frac{6}{x^{2}+4} } \, dx

-\int {\frac{1}{x-5}\, dx + 2\int {\frac{2x}{x^{2}+4}} \, dx - 6\int {\frac{1}{x^{2}+4} } \, dx

-ln|x-5| + 2ln(x^{2}+4) - 6(\frac{1}{2} tan^{-1}(\frac{x}{2} )) + C

-ln|x-5| + 2ln(x^{2}+4) - 3 tan^{-1}(\frac{x}{2} ) + C

5 0
3 years ago
Which pair of points have equal x coordinates?<br>​
olga_2 [115]

Answer:

Q and R

Step-by-step explanation:

Q = (-5, 6)

R = (-5, -7)

They both have the same x-coordinates.

4 0
3 years ago
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