Question

I hate Aleks, please help .

Answer 1

Interesting question! Let's first break this up:
$\frac{4!8!}{2!7!}= \frac{1x2x3x4x1x2x3x4x5x6x7x8}{1x2x1x2x3x4x5x6x7}$

We can now simplify this by crossing out numbers that appear in both denominator and numerator. This becomes
$\frac{3x4}{1}$

Therefore, the answer is 12