The object should be placed 20/cm from the lens so as to form its real image on the screen
<h3>Mirror equation</h3>
The mirror equation is given according to the expression below;
1/f = 1/u + 1/v
where
f is the focal length
u is the object distance
v is the image distance
Given the following parameters
f = 5cm
v = 20cm
Required
object distance u
Substitute
1/5 = 1/u +1/20
1/u = 1/5-1/20
1/u = 3/20
u = 20/3 cm
Hence the object should be placed 20/cm from the lens so as to form its real image on the screen
Learn more on mirror equation here; brainly.com/question/27924393
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the length of segment AB is 13
It’s twelve because you multiple x by 12 and get y.
Consider the digit expansion of one of the numbers, say,
676₉ = 600₉ + 70₉ + 6₉
then distribute 874₉ over this sum.
874₉ • 6₉ = (8•6)(7•6)(4•6)₉ = (48)(42)(24)₉
• 48 = 45 + 3 = 5•9¹ + 3•9⁰ = 53₉
• 42 = 36 + 6 = 4•9¹ + 6•9⁰ = 46₉
• 24 = 18 + 6 = 2•9¹ + 6•9⁰ = 26₉
874₉ • 6₉ = 5(3 + 4)(6 + 2)6₉ = 5786₉
874₉ • 70₉ = (8•7)(7•7)(4•7)0₉ = (56)(49)(28)0₉
• 56 = 54 + 2 = 6•9¹ + 2•9⁰ = 62₉
• 49 = 45 + 4 = 5•9¹ + 4•9⁰ = 54₉
• 28 = 27 + 1 = 3•9¹ + 1•9⁰ = 31₉
874₉ • 70₉ = 6(2 + 5)(4 + 3)10₉ = 67710₉
874₉ • 600₉ = (874•6)00₉ = 578600₉
Then
874₉ • 676₉ = 578600₉ + 67710₉ + 5786₉
= 5(7 + 6)(8 + 7 + 5)(6 + 7 + 7)(0 + 1 + 8)(0 + 0 + 6)₉
= 5(13)(20)(20)(1•9)6₉
= 5(13)(20)(20 + 1)06₉
= 5(13)(20)(2•9 + 3)06₉
= 5(13)(20 + 2)306₉
= 5(13)(2•9 + 4)306₉
= 5(13 + 2)4306₉
= 5(1•9 + 6)4306₉
= (5 + 1)64306₉
= 664306₉
Answer:
Step-by-step explanation:
1) Least common denominator of 4 and 2 is 4
To eliminate the fraction, each term should be multiplied by 4
ANS:option c
2) Mercury level of water 'y' years = Initial measure +rate of increase 'y' years
0.05 +0.1y = 0.12+0.06y
Ans : Option c
3) 4b +6 = 2 - b + 4
Add 'b' to both sides
4b + b + 6 = 2 + 4
5b + 6 = 6
Subtract 6 from both sides
5b = 6 - 6
5b = 0
b = 0
Ans : Option b
4) Maximum decimal places in this equation is 2. So, to eliminate decimal places, The equation should be multiplied by 100
Ans: option d
5) y +6 = -3y + 26
Add 3y to both the sides
y + 6 + 3y = 26
y + 3y + 6 = 26
4y + 6 = 26
Subtract 6 from both sides
4y = 26-6
4y = 20
Divide bothe sides by 4
y = 20/4
y = 5
Ans: option c
6) '2x' is subtracted from both side of the equation.
Ans: option a - subtraction property of equality
