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3 years ago

Given the equation xy+4y=3x-2 show that y is a function of x and determine the domain in interval notation.

1 answer:

7 0

First, the equation has to be rearranged so that y will be isolated on the left-hand side of the equation.

(x + 4)y = 3x - 2y = (3x - 2)/(x + 4)

This form is a rational function which is of course a function. All values of x are possible, except for x when y becomes undefined, thus the domain should be x /= -4. In interval notation, (-inf, -4) U (-4, inf).

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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What is the value of the expression when n=3 -2n(5+n-8-3n)

igor_vitrenko [27]

-2(3)(5+3-8-3(3))
=-6(5+3-8-9)
=-30-18+48+54
=54

4 0

3 years ago

Read 2 more answers

The base is 3 and the height is 2 what is the area of the triangle

Scorpion4ik [409]

Answer:

area = 3

Step-by-step explanation:

area of a triangle = 1/2 base x height

1/2 x 3 x 2 = 1/2 x 6 = 3

6 0

3 years ago

Complete the square to factor X^2 +10X=-8

ella [17]

Answer: $x=\sqrt{17}-5$ and $x = -\sqrt{17}-5$

Step-by-step explanation:

Alright, lets get started.

The given equation is :

$x^{2} +10x = -8$

Adding 8 in both sides, it will become

$x^{2} +10x + 8 = -8 +8$

$x^{2} +10x + 8 = 0$

To make it perfect square, we need to add 25 and subtract 25

$x^{2} +10x + 8 +25-25= 0$

$x^2+10x+25+8-25=0$

$(x+5)^2+8-25=0$

$(x+5)^2-17=0$

Adding 17 in both sides

$(x+5)^2=17$

taking square root

$x+5=\sqrt{17}$

So,

$x=\sqrt{17}-5$ and $x = -\sqrt{17}-5$ .. Answer

Hope it will help :)

7 0

3 years ago

Read 2 more answers

1. What are foci? 2. What is the first step to take to write the equation of a hyperbola? 3. How do you represent parts of a hyp

Andrei [34K]

Answer: see below

<u>Step-by-step explanation:</u>

1) Foci is plural for Focus. Since a hyperbola has two focus points, they are referred to as foci. The foci is where the sum of the distances from any point on the curve to the foci is constant.

2) When determining the equation of a hyperbola you need the following:

a) does the hyperbola open up or to the right?

b) what is the center (h, k) of the hyperbola?

c) What is the slope of the asymptotes of the hyperbola?

3) The equation of a hyperbola is:

$\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1\qquad or\qquad \dfrac{(y-k)^2}{b^2}-\dfrac{(x-h)^2}{a^2}=1$

(h, k) is the center of the hyperbola
± b/a is the slope of the line of the asymptotes
The equation starts with the "x" if it opens to the right and "y" if it opens up

5 0

4 years ago

If UW =9x-9 what is UW as units

Vaselesa [24]

UW is always equal to 9x-9 or 9(x-1) whenever x is a real number. By adding in x, we can get the value.

For example, if x was 4, we add in x, giving us 9*4-9=36-9=27 units or
9(4-1)=9(3)=27 units

Hoped this helped in time!

4 0

3 years ago