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Brut [27]
3 years ago
14

Find the area of each figure.1.12 m8 m​

Mathematics
1 answer:
-Dominant- [34]3 years ago
3 0
The correct answer might be 96?
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Click to see the picture how do i do this!
crimeas [40]

Answer:

Look at the pic

Step-by-step explanation:

I hope I did it right...I haven't touched this topic a long time

8 0
3 years ago
Which graph below shows the object above rotated around the point (4,4)?
faltersainse [42]

Answer:

A. IV

Step-by-step explanation:

The figure is congruent, but rotated. Additionally, the figure is rotated/on point (4,4).

7 0
3 years ago
A boy decided to save by an unusual method.He put 1cent, the first week.2cent in the second week,4xent in the third week,8cent i
lesya692 [45]

Answer:

Step-by-step explanation:

for 1st week=1 ¢

for 2nd week= 2¢

for 3rd week= 4¢

for 4th week=8¢

for 5th week=16¢

for 6th week=32¢

for 7th week=64¢

for 8th week=64+64=128¢

for 9th week= 128+128=256¢

for 10th week= 256+256=512¢

.: he saved a total of

1+2+4+8+16+32+64+128+256+512=1023¢

1023¢=1023/100=$10.23

4 0
3 years ago
Find the distance between points P (-3, 4) and Q (1, 6).
salantis [7]
Just draw a graph and plot them on the graph then count how many squares (in short) there is between them.
7 0
3 years ago
Which choice is equivalent to the expression below when y2 0?<br> √y^2 + √16y^3 – 4y√y
DanielleElmas [232]

Answer:

Option C.

Step-by-step explanation:

We start with the expression:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

where y > 0. (this allow us to have y inside a square root, so we don't mess with complex numbers)

We want to find the equivalent expression to this one.

Here, we can do the next two simplifications:

\sqrt{16*y^3} = \sqrt{16} \sqrt{y^3} = 4*\sqrt{y^3}

And:

y*\sqrt{y} = \sqrt{y^2} *\sqrt{y} = \sqrt{y^2*y} = \sqrt{y^3}

If we apply these two to our initial expression, we can rewrite it as:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

\sqrt{y^3}  + 4*\sqrt{y^3} - 4\sqrt{y^3} = \sqrt{y^3}

Here we can use the second simplification again, to rewrite:

\sqrt{y^3} = y*\sqrt{y}

So, concluding, we have:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y} = y*\sqrt{y}

Then the correct option is C.

8 0
3 years ago
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