Answer:
lol nah <3
Step-by-step explanation:
i would try and help, but not with that trump pfp my dude
Answer:
The correct answer is D.
Step-by-step explanation:
Given:
General equation of second degree
x² + y² + 14 x + 2 y + 14 = 0
We must transform given equation to the canonical form from which we will read requested data.
The canonical form of the circle equation is:
(x - p)² + (y - q)² = r²
Where p and q are the coordinates of the center of the circle and r are radius. (p,q) = (x,y)
x² + 2 · x ·7 + 7² - 7² + y² + 2 · y · 1 + 1 - 1 + 14 = (x+7)² + (y+1) - 49 - 1 + 14 = 0
(x + 7)² + (y + 1)² = 36
We see that p = - 7 , q = - 1 and r = 6
God with you!!!
Answer:
A
Step-by-step explanation:
Answer:
The answer is 75
I need to write atleast 20 letters to answer this so don't worry. Also, can you mark as brainliest
9514 1404 393
Answer:
- vertical shift: 7 (up)
- horizontal shift: 2 (right)
- vertical asymptote: x=2
- domain: x > 2
- range: all real numbers
Step-by-step explanation:
For any function f(x), the transformation f(x -h) +k represents a horizontal shift of h units to the right and k units upward.
Here, the parent function is log₂(x) and the transformation to log₂(x -2) +7 represents translation 2 units right and 7 units upward.
The parent function has a vertical asymptote at x=0, so the shifted function will have a vertical asymptote at x-2=0, or x = 2.
The parent function has a domain of x > 0, so the shifted function will have a domain of x-2 > 0, or x > 2.
The parent function has a range of "all real numbers." Shifting the function vertically does not change that range. The range of the shifted function is still "all real numbers."
The graph is shown below. The vertical asymptote is the dashed orange line.
_____
The "work" is in matching the pattern f(x -h) +k to the function log₂(x -2) +7.