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tatuchka [14]
2 years ago
9

Why are new versions of applications packages released often ​

Computers and Technology
1 answer:
stellarik [79]2 years ago
5 0

Answer:

The answer is "new version of application provides more easy to use".

Explanation:

  • In computer science, an application is a program, that is installed on the computer. There are many types of application software, that are "gaming software, working software, programming software, etc." At the end of time users want some new things in software to know users need programmer developed new versions of the software.
  • The update usually improves the device or service in its current version, whilst an improvement is an entirely new version. Installation is usually free and easy. You also have to wait for updates that are difficult to install.
You might be interested in
in java how do i Write a program that reads a set of integers, and then prints the sum of the even and odd integers.
hammer [34]

Answer:

Here is the JAVA program:

import java.util.Scanner; //to take input from user

public class Main{

public static void main(String[] args) { //start of main function

Scanner input = new Scanner(System.in); // creates Scanner class object  

       int num, integer, odd = 0, even = 0; //declare variables

       System.out.print("Enter the number of integers: "); //prompts user to enter number of integers

       num = input.nextInt(); //reads value of num from user

       System.out.print("Enter the integers:\n"); //prompts user to enter the integers

       for (int i = 0; i < num; i++) { //iterates through each input integer

           integer = input.nextInt(); // reads each integer value

               if (integer % 2 == 0) //if integer value is completely divisible by 2

                   even += integer; //adds even integers

               else //if integer value is not completely divisible by 2

                   odd += integer;  } //adds odd integers

           System.out.print("Sum of Even Numbers: " + even); //prints the sum of even integers

           System.out.print("\nSum of Odd Numbers: " + odd);//prints the sum of odd integers

           }}

Explanation:

The program is explained in the comments mentioned with each line of the code. I will explain the logic of the program with the help of an example.

Suppose user wants to input 5 integers. So,

num = 5

Suppose the input integers are:

1, 2 , 3, 4, 5

for (int i = 0; i < num; i++)  is a for loop that has a variable i initialized to 0. The condition i<num is true because i=0 and num=5 so 0<5. Hence the statements inside body of loop execute.

At first iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 1

if (integer % 2 == 0) checks if integer is completely divisible by 2. The modulo operator is used which returns the remainder of the division and if this remainder is equal to 0 then it means that the integer is completely divisible by 2 and if the integer is completely divisible by 2 then this means the integer is even. 1%2 returns 1 so this means this condition evaluates to false and the integer is not even. So the else part executes:

odd += integer;   this becomes:

odd = odd + integer

odd = 1

Now the value of i is incremented to 1 so i=1

At second iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 2

if (integer % 2 == 0) checks if integer is completely divisible by 2. 2%2 returns 0 so this means this condition evaluates to true and the integer is even. So

even += integer;   this becomes:

even= even+ integer

even = 2

Now the value of i is incremented to 1 so i=2

At third iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 3

if (integer % 2 == 0) checks if integer is completely divisible by 2. 3%2 returns 1 so this means this condition evaluates to false and the integer is odd. So

odd += integer;   this becomes:

odd= odd + integer

odd= 1 + 3

odd = 4

Now the value of i is incremented to 1 so i=3

At fourth iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 4

if (integer % 2 == 0) checks if integer is completely divisible by 2. 4%2 returns 0 so this means this condition evaluates to true and the integer is even. So

even+= integer;   this becomes:

even = even + integer

even = 2 + 4

even = 6

Now the value of i is incremented to 1 so i=4

At fifth iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 5

if (integer % 2 == 0) checks if integer is completely divisible by 2. 5%2 returns 1 so this means this condition evaluates to false and the integer is odd. So

odd+= integer;   this becomes:

odd= odd+ integer

odd= 4 + 5

odd = 9

Now the value of i is incremented to 1 so i=5

When i=5 then i<num condition evaluate to false so the loop breaks. The next two print statement prints the values of even and odd. So

even = 6

odd = 9

Hence the output is:

Sum of Even Numbers: 6                                                                                                           Sum of Odd Numbers: 9  

6 0
3 years ago
Skinner designed a soundproof apparatus, often equipped with a lever or bar, with which he conducted his experiments in operant
Jlenok [28]

Answer: Skinner box

Explanation: Skinner box is referred as the environment to conduct an experiment to observe the natural behavior of the element in a chamber. The Skinner box is also known as operant conditioning chamber. It is most commonly used for the experiments to be conducted with the animals in the operant conditioning chamber for the research purpose.

It is also soundproof tool and also refereed as the lever box as it contains lever .Thus the answer is Skinner box.

5 0
3 years ago
A security administrator wants to empty the DNS cache after a suspected attack that may have corrupted the DNS server. The serve
MAVERICK [17]

Answer:

The easiest method to clear a DNS cache is to use either the command line, PowerShell or Windows Server's DNS Manager

Explanation:

You can use either the ipconfig /flushdns (command line), Clear-DnsClientCache (PowerShell) or DNS->(name)->Clear Cache (from the DNS Manager)

source:

https://activedirectorypro.com/clear-windows-dns-cache/

https://www.technipages.com/flush-and-reset-the-dns-resolver-cache-using-ipconfig

8 0
3 years ago
Read 2 more answers
Write a method that takes a Regular Polygon as a parameter, sets its number of sides to a random integer between 10 and 20 inclu
Fantom [35]

Answer:

Answered below

Explanation:

//Program is written in Java programming language

Class RegularPolygon{

int sides = 0;

int length = 0;

}

public void randomize(RegularPolygon polygon){

int randomSides = (int) 10 + (Math.random() * 20);

double randomLength = 5 + (Math.random() * 11);

polygon.sides = randomSides;

polygon.length = randomLength;

}

8 0
3 years ago
What function(s) does an interpreter perform with the instructions in a high-level programming language?
allochka39001 [22]

Answer:

Translates and Executes.

Explanation:

5 0
3 years ago
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