Question

How many real and imaginary solutions does the equation X^2+x=11 contains?

Answer 1

Answer:

Two

Step-by-step explanation:

x² + x = 11

The degree of a polynomial will always tell us the maximum number of solutions

You have a second degree polynomial, so there are two possible solutions.

They are

$x = \dfrac{1}{2} \left (-1 - 3\sqrt{5} \right )$

and

$x = \dfrac{1}{2} \left (-1 + 3\sqrt{5} \right )$

The diagram below shows that the zeros are at (-3.854,0) and (2,854, 0), which are the decimal equivalents of the roots.