Answer:
The answer is B. Hopefully this helps!
Using the Hardy-Weinberg equations, the percentage of carriers of cystic fibrosis is 8.19%.
<h3>What are the Hardy-Weinberg equations?</h3>
The Hardy-Weinberg equations describe the relationship between alleles in a population that is fairly constant.
The Hardy-Weinberg equations are given below as;

Hardy-Weinberg equations
Percentage of carriers = 2pq
Percentage of carriers = 2 * 0.09 * 0.91 * 100 = 8.19%
Therefore, the percentage of carriers of cystic fibrosis is 8.19%.
Learn more about Hardy-Weinberg equations at: brainly.com/question/16039271
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