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harina [27]
3 years ago
7

In an addition problem this is the name for the numbers being added together to get the sum. Example: In the problem 3 + 4 = 7,

3 and 4 are these.
Mathematics
1 answer:
Lina20 [59]3 years ago
5 0

Those are digits, also known as numbers. There are lot's of other names as well, like real numbers, integers, and so on.

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12. Volume of a cube is 648V3 cm³. Find its total surface<br>area.​
AleksAgata [21]

Answer:

area= 449.2984 cm^2   if I understand correctly that the volume is 648 cm^3

Step-by-step explanation:

side length=the cube root of 648

side length=8.6535 cm

area=8.6536x8.6535x6=449.2984 cm^2

7 0
3 years ago
If a certain cannon is fired from a height of 8.8 meters above the​ ground, at a certain​ angle, the height of the cannonball ab
Dennis_Churaev [7]

Answer:

It would take approximately 6.50 second for the cannonball to strike the ground.

Step-by-step explanation:

Consider the provided function.

h(t)=-4.9t^2+30.5t+8.8

We need to find the time takes for the cannonball to strike the ground.

Substitute h(t) = 0 in above function.

-4.9t^2+30.5t+8.8=0

Multiply both sides by 10.

-49t^2+305t+88=0

For a quadratic equation of the form ax^2+bx+c=0 the solutions are: x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Substitute a = -49, b = 305 and c=88

t=\frac{-305+\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}=-\frac{-305+\sqrt{110273}}{98}\\t = \frac{-305-\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}= \frac{305+\sqrt{110273}}{98}

Ignore the negative value of t as time can't be a negative number.

Thus,

t=\frac{305+\sqrt{110273}}{98}\approx6.50

Hence, it would take approximately 6.50 second for the cannonball to strike the ground.

6 0
3 years ago
Between 3 P.M and 3:30 P.M., the minute hand of a clock moves 180 degrees. How many degrees does the hour hand move during that
AURORKA [14]

Answer:

Between 3 P.M. and 3:30 P.M the hour hand moves 15°.

Step-by-step explanation:

The rotation of the minute hand of a clock between 3 P.M. and 3:30 P.M. is from the the 12 hour mark to the 6 hour mark which is half of one complete cycle

One complete cycle of clock rotation = 360° = 12 hours

Therefore, the hour hand rotates 360/12 = 30° for each hour

Given that the time between 3 P.M. and 3:30 P.M. is 30 minutes = 1/2 an hour

The rotation of the hour hand between 3 P.M. and 3:30 P.M = Half the rotation for 1 hour

∴ The rotation of the hour hand between 3 P.M. and 3:30 P.M = 30°/2 = 15°

Between 3 P.M. and 3:30 P.M the hour hand moves 15°.

4 0
3 years ago
N+6 (10n+7)= simply expression
Aleonysh [2.5K]

Answer:

The correct answer is 61n+42

4 0
3 years ago
Read 2 more answers
Solve and graph the absolute value inequality: |2x + 1| ≤ 5.
bogdanovich [222]
|2x + 1| < = 5

-5 < = 2x + 1 < = 5 ...subtract 1
-5 - 1 < = 2x + 1 - 1 < = 5 - 1
-6 < = 2x < = 4 ....divide by 2
-6/2 < = (2/2)x < = 4/2
-3 < = x < = 2

B. a number line with closed dots (because of the = sign) on -3 and 2 with shading in between
6 0
4 years ago
Read 2 more answers
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