Answer: The answer is 20
Step-by-step explanation: If all interior angles are 162o , polygon has 20 sides.
82*100/40 = 205
<span>40% 0f 205 = 205*40% = 205*40/100 = 82
hopes this helps :) :D :)</span>
Answer:
The vertices of image are (-48,48), (24,24) and (72,96).
Step-by-step explanation:
From the figure it is noticed that the vertices of triangle are (-4,4), (2,2) and (6,8).
The scale factor is 12 and the dilation is about the origin.
If a figure is dilated about the origin with scale factor k, then

Since the scale factor is 12.

The vertices of image are



Therefore the vertices of image are (-48,48), (24,24) and (72,96). The graph of image is shown below.
Answer:
The surface area of the right regular hexagonal pyramid is 50.78 cm².
Step-by-step explanation:
Given:
A right regular hexagonal pyramid with sides(s) 2 cm and slant height(h) 5 cm.
Now, to find the surface area(SA) of the right regular hexagonal pyramid.
So, we find the area of the base(b) first:
Area of the base = ![\sqrt[3]{3}\times s^{2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D%5Ctimes%20s%5E%7B2%7D)
= ![\sqrt[3]{3}\times 2^{2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D%5Ctimes%202%5E%7B2%7D)
On solving we get:
Area of the base(b) = 
Then, we find the perimeter(p) :
Perimeter = s × 6

Now, putting the formula for getting the surface area:
Surface area = perimeter × height/2 + Area of the base.




As, <em>the surface area is 50.784 and rounding to nearest hundredth becomes 50.78 because in hundredth place it is 8 and in thousandth place it is 4 so rounding to it become 50.78.</em>
Therefore, the surface area of the right regular hexagonal pyramid is 50.78 cm².