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3 years ago

Solve the equation. Check your answer. 23 = 7x + 2 - 4x X= 1 (Simplify your answer.)

Mathematics

1 answer:

pychu [463]3 years ago

3 0

Answer:

Step-by-step explanation:

23 = 7x + 2 - 4x

23 = 3x + 2

3x = 21

x = 7.

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#8 What is the VALUE of point B (put in decimal form) *

MakcuM [25]

Answer:

B= -2.75

A= -0.25

C= 2.50

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3 years ago

Part of the arena is being turned into a public darkroom. The floor needs covering in rubber tiles before work can begin on the

vladimir2022 [97]

The number of tiles used is 300 tiles.

According to the statement

We have given that:

The tiles are 20 cm by 30 cm. And the dark room floor is 6 meters by 3 meters.

And we have to find that the number of tiles used to prepare the dark room.

So, For this purpose we have to find the area of the room floor.

The area of the floor is 6 *3.

The area of the floor is 18 meter per square.

The area of the tile is 0.2*0.3

The area of the tile is 0.06 meter per square.

Now,

The number of tiles used is 18/0.06

The number of tiles used is 300.

So, The number of tiles used is 300 tiles.

Learn more about Area here brainly.com/question/10090807

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2 years ago

Figure PQRS is rotated counterclockwise

sleet_krkn [62]

I gotchu fam, a rotation is occurring and we know this because it’s rotating 180°. Figures PQRS and P’Q’R’S’ are congruent because they are the same shape and size, just in different places.

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2 years ago

I need helppp help meeeeeeee

Rama09 [41]

1) $\frac{11-13}{4-7}= \frac{2}{3}$

2) $\frac{-2-7}{-10-(-7)}=\frac{-9}{-3} =3$

3) $\frac{9-3}{-11-(-14)} =\frac{6}{3}=2$

4) $\frac{8-4}{11-(-9)} =\frac{4}{20}= \frac{1}{5}$

ok done. Thank to me :>

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2 years ago

Plz help me with this

Setler79 [48]

Answer: x = 8

(the correct answer was not provided as an option)

<u>Step-by-step explanation:</u>

$log_2(x-6)+log_2(x-4)=log_2(x)\\\\log_2[(x-6)(x-4)]=log_2(x)\\\\(x-6)(x-4)=x\\\\x^2-10x+24=x\\\\x^2-11x+24=0\\\\(x-3)(x-8)=0\\\\x=3\qquad x=8\\\\\\\text{The term after the log symbol (inside the parenthesis) must be greater than 0!}\\\\Check:\\3-6>0\ \text{FALSE --- so 3 is not a valid solution}\\\\8-6>0\ \text{TRUE}\\8-4>0\ \text{TRUE}\\8>0\ \text{TRUE --- 8 is a valid solution because it is true for all}$

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3 years ago