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den301095 [7]
3 years ago
6

64 divided by 13,248

Mathematics
2 answers:
BabaBlast [244]3 years ago
8 0

Answer:

207

Step-by-step explanation:

bixtya [17]3 years ago
5 0
That equals 0.004830917874396
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Question 1(Multiple Choice Worth 1 points)
Romashka [77]

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5%

Step-by-step explanation:

Lets say 10 add a 0 = 100 9.5 add a 0 = 95.0 (move ok decimal place) so there is a 5% error.

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A 9.3 m<br> b. 13.3 m<br> C. 18 m<br> d. 21 m<br><br> Which answer is it
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Step-by-step explanation:

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One over four (4x + 15) = 24
kiruha [24]

Answer:

x = 20 1/4

Step-by-step explanation:

1/4 (4x + 15) = 24

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You buy a book for $12 and a CD for $6. You hand a sales cleck a $20. How much change should you get back?
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3 years ago
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During halftime of a basketball ​game, a sling shot launches​ T-shirts at the crowd. A​ T-shirt is launched from a height of 4 f
Sonbull [250]

Answer:

(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is 4 + 64\cdot t - 16 \cdot  t^{2}

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

h = 4 + 64\times 2 - \frac{1}{2} \times 32  \times  2^{2}

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

(c) The range of the function that models the height of the T-shirt over time given above is derived as

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

h =4 + 64\cdot t - \frac{1}{2} \times 32  \cdot  t^{2} = 4 + 64\cdot t - 16 \cdot  t^{2}.

6 0
3 years ago
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