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Mama L [17]
3 years ago
5

What is an equation of a line, in point-slope form, that passes through (1, −7) and has a slope of −2/3 ?

Mathematics
2 answers:
lawyer [7]3 years ago
7 0
Y-y1=m(x-x1)

substitute

y+7=-2/3(x-1)
y+7=2/3(-x+1)
or
y+7=-2/3x +2/3


i have no idea what those options are for but the most likely answer looks like option A
Andrews [41]3 years ago
6 0

Answer:- A. y+7=\frac{-2}{3}(x-1)


Explanation:-

We know that the equation of a line passing through point (a,b) whose slope is m, is

(y-b)=m(x-a)

Thus, the equation of a line passing through point (1, −7) whose slope \frac{-2}{3} is ,

(y-(-7))=\frac{-2}{3}(x-1)

\\\Rightarrow(y+7)=\frac{-2}{3}(x-1)

∴ A. is the right answer. The equation of a line passing through point (1, −7) whose slope \frac{-2}{3} is (y+7)=\frac{-2}{3}(x-1).

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an archaeologist in turkey discovers a spear head that contains 80% of its original amount of C-14. Find the age of the spear he
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P(t)=P_0(\frac{1}{2})^{\frac{t}{5730} }

an archaeologist in turkey discovers a spear head that contains 80% of its original amount of C-14

so,

P(t)=0.80P_0

we can plug it

0.80P_0=P_0(\frac{1}{2})^{\frac{t}{5730} }

now, we can solve for t

0.80=(\frac{1}{2})^{\frac{t}{5730} }

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Find the diagram attached

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x = 3 * √2

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Hence the value of x is 3√2

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