Answer: Option D

Step-by-step explanation:
For a quadratic function of the form
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The x coordinate of the vertice is:

In this case the function is:

So

The x coordinate of the vertice is:

The y coordinate of the vertice is:

The vertice is: (-3, -11)
The form e vertice for a quadratic equation is:

Where
the x coordinate of the vertice is h and the y coordinate of the vertice is k.
Then h=-3 and k =-11
Finally the equation
in vertex form is:

Answer:
the first one is m, the second one is 5
Answer:
11 : 38
Step-by-step explanation:
<span>Simplifying
1.06g + -3 = 0.71
Reorder the terms:
-3 + 1.06g = 0.71
Solving
-3 + 1.06g = 0.71
Solving for variable 'g'.
Move all terms containing g to the left, all other terms to the right.
Add '3' to each side of the equation.
-3 + 3 + 1.06g = 0.71 + 3
Combine like terms: -3 + 3 = 0
0 + 1.06g = 0.71 + 3
1.06g = 0.71 + 3
Combine like terms: 0.71 + 3 = 3.71
1.06g = 3.71
Divide each side by '1.06'.
g = 3.5
Simplifying
g = 3.5</span>
Yeah definitely the first guy