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Artist 52 [7]
3 years ago
8

Can someone please help me with my algebra fraction homework pages 8,9 and 10. Thank you!

Mathematics
1 answer:
Alecsey [184]3 years ago
6 0

Answer:

Step-by-step explanation:

#8 the answer is A

using special products, fact the denominator of both fractions

q^2+5q+6 is the same as (q+2)(q+3)

q^2+3q+2 is the same as (q+2)(q+1)

no you have to find the lease common denominator of the two fractions

multiply the first fraction by (q+1)/(q+1)

multiply the second fraction by (q+3)/(q+3)

you will get (q^2+2q+3)/(q+1)(q+2)(q+3) after you combine like terms and stuff like that.

#9 the answer is C

using special products factor the numerator of the first fraction, and the denominator of the second fraction

r^2+7r+10 is the same as (r+2)(r+5)

r^2-5r-50 is the same as (r-10)(r+5)

then factor the numerator if the second fraction

3r-30 is the same as 3(r-10)

is the second fraction there is (r-10) in the numerator and denominator, simplify that.

then simplify the 3, and the (r+5)

you will be left with r+2 from the first fraction

#10 the answer is A

when you divide same base exponents, you subtract their powers

so

x^0/x^2 = x^-2       and

y^-3/y^-1=y^=2

so you are left with x^-2*y^-2 but that is not an option

we also know that negative exponents is the same thing as the reciprocal with the exponent in the denominator

x^-1 = 1/x

so

x^-2*y^-2 = 1/x^2*y^2

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Answer:

Angle F = 140°

Step-by-step explanation:

Add up all the angles and set it equal to 720°

x-20+x-40+x-60+130+120+110=

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Add the x's together. And the numbers together.

3x - 120 + 360 =720

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Subtract 240.

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Divide by 3.

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Now find Angle F.

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A = {1,3,5,6,7,8,9}<br> B = {3,7,12,13,14}<br> 6) ANB<br> 7) AUB<br><br> How do I solve this?
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A line segment has (x1, y1) as one endpoint and (xm, ym) as its midpoint. Find the other endpoint (x2, y2) of the line segment i
Tasya [4]

Answer:

(3,7) for the first line, and (12,0) for the second one.

Step-by-step explanation:

Hi Isabella,

1) The Midpoint of a line, when it comes to Analytical Geometry, is calculated as Mean of two points it follows:

x_{m}=\frac{x_{1} +x_{2} } {2}, y_{m} =\frac{y_{1}+ y_{2} }{2}

2) Each segment has two endpoints, and their midpoints, namely:

a) (1,-9) and its midpoint (2,-1)

b) (-2,18) and its midpoint (5,9)

3) Calculating. You need to be careful to not sum the wrong coordinates.

So be attentive!

The first line a

2=\frac{1+x_{2} }{2}\\  4=1+x_{2}\\  4-1=-1+1+x_{2} \\ x_{2}=3\\-1=\frac{y_{2}-9}{2}\\-2=y_{2}-9\\+2-2=y_{2}-9+2\\ y_{2}=-7

So (3,7) is the other endpoint whose segment starts at (1,-9)

The second line b endpoint at (-2,18) and its midpoint (5,9)

5=\frac{-2+x_{2} }{2} \\ 10=-2+x_{2} \\ +2+10=+2-2+x_{2}\\ x_{2}=12 \\ \\ 9=\frac{18+y_{2} }{2} \\ 18=18+y_{2} \\ -18+18=-18+18+y_{2}\\ y_{2} =0

So (12,0) it is the other endpoint.

Take a look at the graph below:

8 0
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