Answer:
Step-by-step explanation:
#8 the answer is A
using special products, fact the denominator of both fractions
q^2+5q+6 is the same as (q+2)(q+3)
q^2+3q+2 is the same as (q+2)(q+1)
no you have to find the lease common denominator of the two fractions
multiply the first fraction by (q+1)/(q+1)
multiply the second fraction by (q+3)/(q+3)
you will get (q^2+2q+3)/(q+1)(q+2)(q+3) after you combine like terms and stuff like that.
#9 the answer is C
using special products factor the numerator of the first fraction, and the denominator of the second fraction
r^2+7r+10 is the same as (r+2)(r+5)
r^2-5r-50 is the same as (r-10)(r+5)
then factor the numerator if the second fraction
3r-30 is the same as 3(r-10)
is the second fraction there is (r-10) in the numerator and denominator, simplify that.
then simplify the 3, and the (r+5)
you will be left with r+2 from the first fraction
#10 the answer is A
when you divide same base exponents, you subtract their powers
so
x^0/x^2 = x^-2 and
y^-3/y^-1=y^=2
so you are left with x^-2*y^-2 but that is not an option
we also know that negative exponents is the same thing as the reciprocal with the exponent in the denominator
x^-1 = 1/x
so
x^-2*y^-2 = 1/x^2*y^2
