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3 years ago

Find the missing coefficient. - y2 − [-5y − y(-7y − 9)] − [-y (15y + 4)] = 0

Mathematics

2 answers:

Ber [7]3 years ago

6 0

Answer:

its -8 if ur on plato be careful the negetive sign is already there <3

Step-by-step explanation:

have a good day

maria [59]3 years ago

5 0

There is only one solution in the given equation -y2 − [-5y − y(-7y − 9)] − [-y (15y + 4)] = 0. In solving this problem, apply first PEMDAS (parenthesis, exponents,multiplication, division, addition, subtraction). Then equation will transform into -y2+5y-7y2-9y+15y2+4y=0. Combine terms with same power and achieve 7y2=0. Divide both sides with 7 and perform square root of zero. Since the root is zero, we have one solution of the given equation which is y=0.

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(50 points) Which graph is defined by the function given below?

marta [7]

Answer:

Graph B

Step-by-step explanation:

y = (x - 3)(x - 3)

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2 years ago

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adelina 88 [10]

Answer:

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Step-by-step explanation:

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2 years ago

Is 9/15 irrational??

Mariana [72]

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4 0

3 years ago

Read 2 more answers

Determine if there is a proportional relationship between the two quantities

Shalnov [3]

Answer:

The table a not represent a proportional relationship between the two quantities

The table b represent a proportional relationship between the two quantities

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

Verify each table

Table a

Let

A ----> the independent variable or input value

B ----> the dependent variable or output value

the value of k will be

$k=\frac{B}{A}$

For A=35, B=92 ---> $k=\frac{92}{35}=2.63$

For A=23, B=80 ---> $k=\frac{80}{23}=3.48$

the values of k are different

therefore

There is no proportional relationship between the two quantities

Table b

Let

C ----> the independent variable or input value

D ----> the dependent variable or output value

the value of k will be

$k=\frac{D}{C}$

For C=20, D=8 ---> $k=\frac{8}{20}=0.40$

For C=12.5, D=5 ---> $k=\frac{5}{12.5}=0.40$

the values of k are equal

therefore

There is a proportional relationship between the two quantities

The linear equation is equal to

$D=0.40C$

7 0

3 years ago

Calculate the second moment of area of a 4-in-diameter shaft about the x-x and yy axes, as shown.

Keith_Richards [23]

Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.

The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.

6 0

3 years ago