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STatiana [176]
3 years ago
8

Suppose we want to choose for letters without replacement from 18 distant lovers how many ways can this be done if the order of

the choices does not matter
Mathematics
1 answer:
Lelu [443]3 years ago
7 0

Answer:

This can be done in 3,060 ways.

Step-by-step explanation:

Letters are chosen without replacement, and the order does not matter, which means that the combinations formula is used.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Four letters from a set of 18. So

C_{18,4} = \frac{18!}{4!14!} = 3060

This can be done in 3,060 ways.

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Hi there

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3 years ago
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now, we can draw triangle and then switch vertices accordingly

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Step-by-step explanation:

<u>Explanation</u>:-

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