The enclosed shape is that of a trapezoid. The area of a trapezoid is the product of the height of it (measured perpendicular to the parallel bases) and the average length of the two parallel bases. The formula is generally written ...
... A = (1/2)(b₁ + b₂)·h
Here, the base lengths are the y-coordinates at x=4 and x=9. The height is the distance between those two x-coordinates: 9 - 4 = 5.
You are expected to find the y-values at those two points, then use the formula for the area of the trapezoid.
You can save a little work if you realize that the average of the two base lengths is the y-coordinate corresponding to the average x-coordinate: (9+4)/2 = 6.5. That is you only need to find the y-coordinate for x=6.5 and do the area math as though you had a rectangle of that height and width 5.
Going that route, we have
... y = 2(6.5) - 1 = 13 - 1 = 12
Then the trapezoid's area is
... A = 12·5 = 60 . . . . square units.
Slope-intercept forms:
line r= y= 2/5x+2
line s= y= -3/2x+3
line T= y= -2/3x-2
9514 1404 393
Answer:
x = 15
Step-by-step explanation:
Corresponding sides are proportional, so the ratios of bottom to left side are the same. The left side of the large triangle is 6+4=10.
x/10 = 9/6
x = 10(9/6) . . . . multiply by 10
x = 15
2 is the answer
Division is finding the number of times a number can be put into another number
Answer:
El área de un rectángulo de largo L y ancho A es: L*A.
El área de un triangulo de alto H y base B es: H*B/2.
Ahora veamos las tres figuras:
Rectángulo amarillo:
Largo = 40m
Ancho = 45m
Área = 40m*45m = 1800 m^2
Rectángulo blanco:
Largo = 40m
Ancho = 35m
Área = 40m*35m = 1400m^2
Triangulo azul:
Base = 35m
Alto = 50m
Área = 35m*50m/2 = 875m^2
Area total = 1800 m^2 + 1400m^2 + 875m^2 = 4075m^2
