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KengaRu [80]
3 years ago
11

Write an equation of the line that passes through the points (0, 3) and (-5, 0).

Mathematics
2 answers:
Pie3 years ago
7 0

(0, 3) is the y-intercept as it passes through y = 3 at x = 0, or the y-axis.

Slope:

\frac{y1 - y0}{x1 - x0}  =  \frac{3 - 0}{0 - ( - 5)}  =  \frac{3}{5}

Equation of a straight line:

y = mx + c

m = slope (3/5)

c = y value of y-intercept (3)

Equation:

y =  \frac{3}{5} x + 3

Setler [38]3 years ago
5 0

Answer:

y-3=3/5x

Step-by-step explanation:

y-y1=m(x-x1)

Where m=slope and (x1, y1) is a point on the line.

m=(y2-y1)/(x2-x1)

m=(0-3)/(-5-0)

m=-3/-5

m=3/5

y-3=3/5(x-0)

y-3=3/5(x)

y-3=3/5x

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