So let's start from the beginning.
Add 2 and 4:
(2 + 4)
Multiply the sum by 3:
3(2 + 4)
Then add 5 to that product:
3(2 + 4) + 5
Then double the results:
2[3(2 + 4) + 5]
In the first box is 2.
second box 1.
third 4.
fourth 5.
fifth 3.
1)
log 98 = log( 7 * 14 ) = log 7+ log 14= h + j ;
2)
log 175 = log ( 5^2 * 7 ) = log 5 ^ 2 + log 7 = 2 * log 5 + log 7 = 2i + h ;
3)
log 2 = log ( 14 / 7 ) = log 14 - log 7 = j - h ;
4)
log 245 = log ( 7^2 * 5 ) = log 7 ^2 + log 5 = 2 * log 7 + log 5 = 2h + i ;
