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adell [148]
3 years ago
9

You have 60.00 in your wallet and you want to buy some new cds. if the cd's are 11.00 each, what number of cd's x can you buy?wr

ite and solve an inequality. then explian your answer.
Mathematics
1 answer:
Dvinal [7]3 years ago
3 0
You have $60.00.
Each CD (x) is $11.00.

11x ≤ 60
The number of CDs multiplied by the cost (11) has to be less than or equal to 60. 
x ≤ 5.45

You can only buy 5 CDs.
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I’m a little confused with this? Can someone walk me through this?
mina [271]

Answer:

A. 5.8

Step-by-step explanation:

From the given graph d has two coordinates;

the first coordinates of d = (0, 0)

the second coordinate of d = (-3 , -5), that is x = -3 when traced up and y = -5 when traced horizontal

The distance between the two coordinates = distance of d;

distance \ between \ two \ coordinates = \sqrt{(x_2-x_1)^2 \ + \ (y_2-y_1)^2} \\\\d =  \sqrt{(-3-0)^2 \ + \ (-5-0)^2}\\\\d = \sqrt{9 \ + \ 25} \\\\d = \sqrt{34} \\\\d = 5.83\\\\d = 5.8

Option A is correct

6 0
3 years ago
5×+9y, when x=8 and y=11
vovikov84 [41]

Answer:

40+99

139

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
A corporate bond has a coupon rate of 5.5 percent, a $1,000 face value, and matures three years from today. The corporation is i
melomori [17]

Answer:

= \frac{\frac{75}{100}\times 1000 + \frac{25}{100} \times \frac{60}{100}\times 1000  }{(1+\frac{15}{100})^3 }

=\frac{0.75\times 1000 + 0.25\times 0.60 \times 1000}{(1+0.15)^3}

=\frac{750+0.25\times 0.60\times 1000}{1.15^3} \\\\=\frac{750+150}{1.520875} =\frac{900}{1.520875} \\\\=591.76

Step-by-step explanation:

= (probability of entire face value paid*face value+probability of entire face value not paid*percent of face value paid*face value)/(1+discount rate)^years to maturity

probability of entire face value paid = 75%

face value = 1000

probability of entire face value not paid = 25%

percent of face value paid= 60%

discount rate = 15%

years to maturity  = 3

= \frac{\frac{75}{100}\times 1000 + \frac{25}{100} \times \frac{60}{100}\times 1000  }{(1+\frac{15}{100})^3 }

=\frac{0.75\times 1000 + 0.25\times 0.60 \times 1000}{(1+0.15)^3}

=\frac{750+0.25\times 0.60\times 1000}{1.15^3} \\\\=\frac{750+150}{1.520875} =\frac{900}{1.520875} \\\\=591.76

6 0
2 years ago
In a hospital there are 56 TB patients. The patients are grouped with respect to their ages.
zalisa [80]
<span>Table:

Class Boundaries         Frequency

5-10                              8

10-15                            9

15-20                          15

20-25                          10

25-30                           8

30-35                           6
                                ----------
total                           56

Average =

[5+10]/2*8+[10+15]/2*9+[15+20]/2*15+[20+25]/2*10+[25+30]/2*8+[30+35]/2*6
---------------------------------------------------------------------------------------------------
</span>                                                      56

That is 1075 / 56 = 19.2

Answer: 19

5 0
3 years ago
I'm completely lost
Vladimir [108]
Let x be the number of racing bikes, and let y be the number of mountain bikes.
1) 140x + 110y = 26150
2) 180x + 120y = 31800
Solve for one of the variables and plug that in to the other equation:
From equation 1: 140x = 26150 - 110y
x = (26150-110y)/140
Plug this into equation 2:
180((26150-110y)/140) = 31800
Solve for y, and find that y = 85 (the number of mountain bikes).
Plug that y into either equation to find x:
140x + 110(85) = 26150
x = 120 (the number of racing bikes).
So the answer is: 120 racing bikes and 85 mountain bikes.
4 0
3 years ago
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