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3 years ago

5

ms.Holloway is putting up a bulletin board about frogs. The bulletin board is 6 feet wide and 4 feet tall. she wants to put a bo

rder around the board. what is the distance around the edge of the bulletin board?

1 answer:

Annette [7]3 years ago

6 0

The distance around the bulletin board would be 20 feet, because you multiply 6ft 2x and 4ft 2x.

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Two physics students are doing a side competition during a game of bowling, seeing who can toss a ball with the larger momentum.

dem82 [27]

Answer:

she should beat a speed of v₂ = 6.04 m/s in order to win the competition

Step-by-step explanation:

Since the momentum p is defined as

p = m*v

where

m= mass of the ball

v= velocity of the ball

denoting 1 and 2 as the first and second bowler , then to reach the momentum of the first bowler

p₂=p₁

therefore

m₁*v₁ = m₂*v₂

v₂ = v₁ * (m₁/m₂)

replacing values

v₂ = v₁ * (m₁/m₂) =8.6 m/s * (4.5 kg/6.4 kg ball) = 6.04 m/s

then since the momentum p = m*v increases with increasing v (at constant m) , she should beat a speed of v₂ = 6.04 m/s in order to win the competition

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3 years ago

What is the slope intercept form of <br>(0,2)(-3,7)

Ulleksa [173]

Answer:

$\frac{7 - 2 }{ - 3 - 0} = m(slope)$

Step-by-step explanation:

$\frac{y2 - y1}{x2 - x1} = m(slope)$

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3 years ago

Given: △RST ~ △VWX

tatiyna

Answer:

Given

Step-by-step explanation:

Given that: △RST ~ △VWX, TU is the altitude of △RST, and XY is the altitude of △VWX.

Comparing △RST and △VWX;

TU ~ XY (given altitudes of the triangles)

<TUS = <XYW (all right angles are congruent)

<UTS ≅ <YXW (angle property of similar triangles)

Thus;

ΔTUS ≅ ΔXYW (congruent property of similar triangles)

<UTS + <TUS + < UST = <YXW + <XTW + <XWY = $180^{0}$ (sum of angles in a triangle)

Therefore by Angle-Angle-Side (AAS), △RST ~ △VWX

So that:

$\frac{TU}{XY}$ = $\frac{US}{YW}$ (corresponding side length proportion)

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3 years ago

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Answer:

A ig But ask mrs boomhower or mrs martinez reject

Step-by-step explanation:

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2 years ago

Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are 36 and 2304, respectively.

poizon [28]

Answer:

$a_n=9(4^{n-1})$

Step-by-step explanation:

we know that

In a <u>Geometric Sequence</u> each term is found by multiplying the previous term by a constant, called the common ratio (r)

In this problem we have

$a_2=36\\ a_5=2,304$

Remember that

$a_2=a_1(r)$ -----> $36=a_1(r)$ -----> equation A

$a_5=a_4(r)$

$a_5=a_3(r^{2})$

$a_5=a_2(r^{3})$

Substitute the values of a_5 and a_2 and solve for r

$2,304=36(r^{3})$

$r^{3}=2,304/36$

$r^{3}=64$

$r=4$

Find the value of a_1 in equation A

$36=a_1(4)$

$a_1=9$

therefore

The explicit rule for the nth term is

$a_n=a_1(r^{n-1})$

substitute

$a_n=9(4^{n-1})$

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3 years ago