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Sloan [31]
3 years ago
13

Enter the value of (1)(-8) (4)​

Mathematics
2 answers:
Licemer1 [7]3 years ago
5 0

Answer:

-32

Step-by-step explanation:

Vladimir [108]3 years ago
5 0

Hey there!

The answer to your question is -32

(1)(-8)

-8

(-8)(4)

-32

Hope this helps! Good luck and have a great day!

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CAN SOMEONE EXPLAIN AND MAYBE SHOW ME STEP BY STEP WHY THE ANSWER IS 75degrees. HURRY 50 points and brainiest!!!
KonstantinChe [14]

Answer:

75 degrees, we know that already so look below lol.

Step-by-step explanation:

This triangle is an isosceles triangle, LP is equivalent to LQ, and angles LQP and LPQ are also equivalent. We understand that PLQ is equal to 30 degrees, since its complementary to triangle LQM.

180 - 30 = 150

150/2 = 75.

<em>Have a nice day, fam. Spread The Love. Thanks for the opportunity.</em>

3 0
2 years ago
Read 2 more answers
What are the zeros of the function f(x) = x2 + 8x + 4, expressed in simplest radical form?
klio [65]

Answer:

x = -4 ± 2√3

Step-by-step explanation:

6 0
3 years ago
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X^2-7x-6=0<br> Use the quadratic formula to complete the equation show step by step
asambeis [7]

Answer:

x  = 7  ± √73   / 2



3 0
3 years ago
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What are the roots of the quadratic equation 2x2+7x+4=0? Select all that apply.
skad [1K]

Answer:

option A and B

x=\frac{-7+\sqrt{17}} {4}

and

x=\frac{-7-\sqrt{17}} {4}

Step-by-step explanation:

we have

2x^2+7x+4=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

2x^2+7x+4=0

so

a=2\\b=7\\c=4

substitute in the formula

x=\frac{-7\pm\sqrt{7^{2}-4(2)(4)}} {2(2)}

x=\frac{-7\pm\sqrt{17}} {4}

so

x=\frac{-7+\sqrt{17}} {4}

and

x=\frac{-7-\sqrt{17}} {4}

7 0
3 years ago
The graph of the piecewise function f(x) is shown what is the domain of f(x)
Rom4ik [11]

The domain of a function is where we have a value for x.

Since that's the case the domain of f(x) = {x e R / 1 ≤ x < 5}

We see that we have a value for x = 1 cuz we have a filled circle, but we don't have a value for x = 5, look at the unfilled circle

So, our x can vary between 1 and 5, but can't be 5.

8 0
3 years ago
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