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viva [34]
3 years ago
10

Refer to the cladogram shown above. The

Biology
2 answers:
Gnom [1K]3 years ago
8 0

Answer:

The correct answer is B.C

Explanation:

A cladogram is a diagram used to show the evolutionary relationship between different species and used to find out their most common recent ancestor that means from whom they are evolved or descended.  

Each node represents the common ancestor which descends into two branching lines. These two branching line shows the two descendants from the same common ancestor. So each node represents the common ancestor.  

Therefore in this question, C is the most recent common ancestor for species 4 and A is the most recent common ancestor for species 1 but A and B is can not be an ancestor of species 4 because number 4 species have descended earlier than 3, 2, and 1 species as shown in the cladogram.

As number 1 species is the last descendent so it has all A,B, C and D as its common ancestor but 4th species has only C and D as its common ancestor. So as C is the most common recent ancestor of species 4, therefore, the most common recent ancestor for species 1 and 4 is C.  

Therefore the correct answer is B.C

Vlad [161]3 years ago
7 0

Answer:

i'm like 100% positive its answer  A

Explanation:

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A fish maintains its depth in fresh water by adjusting the air content of porous bone or air sacs to make its average density th
Volgvan

Answer:

0.153

Explanation:

We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.

So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac.

ρVg = ρ'V'g + ρ"V"g

ρV = ρ'V'g + ρ"V"

Its new body volume = volume of water displaced, V = V' + V"

ρ(V' + V") = ρ'V' + ρ"V"

ρV' + ρV" = ρ'V' + ρ"V"

ρV' - ρ"V'  = ρ'V" - ρV"

(ρ - ρ")V'  = (ρ' - ρ)V"

V'/V" = (ρ - ρ")/(ρ' - ρ)

= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³)

= (0.9988 g/cm³ ÷ 0.18 g/cm³)

V'/V" = 5.55

Since V = V' + V"

V' = V - V"

(V - V")/V" = 5.55

V/V" - V"/V" = 5.55

V/V" - 1 = 5.55

V/V" = 5.55 + 1

V/V" = 6.55

V"/V = 1/6.55

V"/V = 0.153

So, the fish must inflate its air sacs to 0.153 of its expanded body volume

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