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3 years ago

6+7 (12-5^2) equals?

Mathematics

2 answers:

pickupchik [31]3 years ago

8 0

-85 is the answer (calculator)

Nadya [2.5K]3 years ago

6 0

The correct answer is -85.

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Can yall help meee please

alexira [117]

Answer:

$jupiters \: mass \: is \: approximatelty \: \\ \boxed{{6 \times 10}^{3} \: kg} \: times, \: \\ more \: than \: mercurys \: mass$

Step-by-step explanation:

$............................................................... \\ in \: other \: to \: get \: right \: ans \to \\ you \: divide \: mass \: of \: jupiter \: by \: the \: mass \\ \: of \: mercury : \: so \to \\ ............................................................... \\ jupiters \: mass = 1.898 { \times 10}^{27} \: kg \\ mercurys \: mass =3.3 \times {10}^{23} \: kg \\ their \: mass \: ratio \: is : \\ = \frac{1.898 { \times 10}^{27}}{3.3 \times {10}^{23}} = 0.5751515152 \times {10}^{4} = \\ \boxed{5,751.515152} \\ hence \: jupiters \: mass \: is \: approximatelty \: \\ {6 \times 10}^{3} \: times \: more \: than \: mercurys \: mass$

5 0

3 years ago

Read 2 more answers

A box of pencils is 5 1/4 inches wide. Seven pencils, laid side by side, take up 2 5/8 inches of the width. How many inches of t

Andre45 [30]

Answer: Width of box is not taken up by pencils = $2\dfrac58\text{ inches}$

Width of each pencil $=\dfrac38\text{ inches}$

Step-by-step explanation:

Given: Width of pencil box = $5\dfrac14\text{ inches}=\dfrac{21}{4}\text{ inches}$

Width of seven pencils = $2\dfrac58\text{ inches}=\dfrac{16+5}{8}\text{ inches}=\dfrac{21}{8}\text{ inches}$

Width of box is not taken up by pencils = Width of pencil box - Width of seven pencils

$\left \{ {{y=2} \atop {x=2}} \right. \dfrac{21}{4}-\dfrac{21}{8}\\\\=\dfrac{21\times2-21}{8}\\\\=\dfrac{21}{8}\text{ inches}=2\dfrac58\text{ inches}$

Width of box is not taken up by pencils = $2\dfrac58\text{ inches}$

Width of each pencil = (Width of seven pencils ) ÷ 7

$=\dfrac{21}{8}\div7\\\\=\dfrac{21}{8}\times\dfrac17\\\\=\dfrac38\text{ inches}$

Width of each pencil $=\dfrac38\text{ inches}$

3 0

3 years ago

Read 2 more answers

If two side of a right angle triangle is 25cm and 15cm what is the length of the unknown side

Studentka2010 [4]

Answer:

29.2 cm

Step-by-step explanation:

The two leg lengths are 15 and 25 cm and we are to find the length of the hypotenuse. The Pythagorean Theorem applies here because this is a right triangle.

a^2 + b^2 = c^2 becomes 15^2 + 25^2 = 225 + 625 = 850

The hypotenuse length is thus √850 ≈ 29.2 cm

5 0

3 years ago

2/7+2/5=answernin simplest form

MrRa [10]

Answer:24/34

Step-by-step explanation:

5 0

4 years ago

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What is the highest mountain in the world?

Rainbow [258]

The highest mountain in the whole world is Mount Everest.
The mountain is located in the Mahalangur section of the Himalayas.
Mount Everest is 8,848 m (29,029 ft), making it the highest mountain in the world.

3 0

4 years ago

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