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tresset_1 [31]
3 years ago
12

Whats the LCM of 5 and 60?

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
5 0
It’s 60...................
Vika [28.1K]3 years ago
3 0
The least common Multiple of 5 and 60 is 60.

Hope this helps!
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Anna [14]
The answer would be D and E

Explanation: the number line shows any number less than 16, the filled in circle also means including 16. So it becomes any number 16 or less. So in both of the scenarios the max number of either students or dollars has to be 16.

Hope this helps
3 0
3 years ago
Read 2 more answers
Herald was making a recipe that needs 1/2 cup of vegetable oil and 1/8 cup of olive oil. How much oil does it need in all?
zaharov [31]

Answer:

\frac{5}{8} of oil.

Step-by-step explanation:

Firstly, you need to find the LCD (lowest common denominator), this can be done by factoring the denominators and knowing the multiples.

In this case, you can see that 2 is a factor of 8 so we can simply multiply \frac{1}{2} so that the denominator is 8:

8 ÷ 2 = 4

\frac{1 * 4}{2 * 4} = \frac{4}{8}

Now the fractions can be added easily:

\frac{4}{8} + \frac{1}{8} = \frac{4 + 1}{8}

= \frac{5}{8} of oil.

Hope this helps!

6 0
3 years ago
What is the volume of a prism that is 7 meters high has a 24 meters base and a 22 meter length
WINSTONCH [101]
Add it all up it's 53

8 0
3 years ago
A farmer finds that if she plants 50 trees per acre, each tree will yield 80 bushels of fruit. She estimates that for each addit
pashok25 [27]

Answer:

28

Step-by-step explanation:

From the given information:

Let x be the number of trees.

F(x) = (50 +x) (20 - 3x)

F(x) = 1000 - 150x + 20x - 3x²)

F(x) = -3x² - 130x + 1000

Differentiating F(x) with respect to x;

F'(x) = \dfrac{d}{dx}( -3x^2- 130x + 1000)

F'(x) = ( -3(2x)- 130(1) +0)

F'(x) = -6x -130

Now; we set F'(x) to be equal to zero to determine the critical value;

-6x - 130 = 0

x = - 130/6

Differentiating F''(x) with respect to x

F''(x) = \dfrac{d}{dx}( -6x- 130)

F''(x) = ( -6(1))

F''(x) = -6 (<0)

Thus; by the second derivative, the revenue function F(x) is maximum when x = -130/6

Therefore, the number of trees she should plant per acre to maximize her harvest is:

50 + x = 50 - 130/6

= 85/3

\simeq 28

Therefore, the number of trees per acre to maximize the harvest is 28

6 0
3 years ago
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