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Hoochie [10]
3 years ago
13

How can I create an app ? What should I download from the App Store ? How can I put my app in the App Store ? PLEASE GIVE ME THE

BRAINLIEST ANSWERS I NEED AN ANSWER FOR MY LITTLE SISTER'S HOMEWORK
Computers and Technology
2 answers:
kirill115 [55]3 years ago
7 0
Its hard but u gotta bring the book of technolgy and Searcy for it in the book by the way there r three books only one of them is avalabile on app store with 100 dollars dont wurry i acan buy it for u
crimeas [40]3 years ago
6 0
It's not easy to create an app for cellphones it is harder than to create those for computers. You would need to learn swift coding language to create an application. 
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Write the definition of a function minMax that has five parameters. The first three parameters are integers. The last two are se
guapka [62]

void minMax(int a, int b, int c, int*big, int*small)

{

if(a>b && a >c){

*big = a;

if(b>c)

*small = c;

else

*small = b;

}

else if (b>a && b>c){

*big = b;

if(a>c)

*small = c;

else

*small = a;

}

else{

*big = c;

if(a>b)

*small = b;

else

*small = a;

}

}

8 0
2 years ago
Generally, websites ending in .edu, .gov, and .org are less likely to be biased, or to show preference toward a certain financia
svetlana [45]

Answer:

True

Explanation:

Domain extensions always appear at the end of a website's address.

It's a means to categorise websites.

.edu domains are used for educational purposes

.gov are restricted to by government entities

.org is largely used by nonprofit websites.

While

.net is derived from the word network, indicating it was originally intended for organizations involved in networking technologies, such as Internet service providers and other infrastructure companies

.biz is intended for registration of domains to be used by businesses

The right domain extension adds credibility and memorability to your website by aligning it with a specific brand purpose.

8 0
3 years ago
Charging current being returned to the battery is always measured in DC Amps. true or false
Rom4ik [11]

Answer:Charging current being returned to the battery is always measured in DC Amps. Electrical energy will always flow from an area of low potential to an area of high potential. ... One volt is the pressure required to force one amp of current through a circuit that has 1 Ohm of resistance.

Explanation:

5 0
2 years ago
Recall that within the ArrayBoundedQueue the front variable and the rear variable hold the indices of the elements array where t
Citrus2011 [14]

Answer:

int n = elements.length;

if(rear < n) {

rear = (rear + 1) % n;

elements[rear] = element;

rear = rear + 1;

}

Explanation:

Options are not made available; However, I'll answer the question base on the following assumptions.

Assumptions

Array name = elements

The front and the rear variable hold the current indices elements

Element to enqueue is "element" without the quotes

To enqueue means to add an element to an already existing queue or to a new queue.

But first, the queue needs to be checked if it can accept a new element or not; in other words, if it's full or not

To do this, we check: if rear < the length of the queue

If this statement is true then it means the array can accept a new element; the new element will be stored at elements[rear] and the rear will be icremented by 1 rear by 1

Else if the statement is false, then an overflow is said to have occurred and the element will not be added.

Going by the above explanation, we have

int n = elements.length;

if(rear < n) {

rear = (rear + 1) % n;

elements[rear] = element;

rear = rear + 1;

}

Additional explanation:

The first line calculates the length of the queue

The if condition on line 2 tests if the array can still accept an element or not

Let's assume this statement is true, then we move to liine 3

Line 3 determines the new position of rear.

Let's assume that n = 6 and current rear is 4.

Line 3 will produce the following result;

rear = (rear + 1) % n;

rear = (4 + 1)% 6

rear = 5%6

rear = 5.

So, the new element will be added at the 5th index

Then line 4 will be equivalent to:

elements[rear] = element;

elements[5] = element;

Meaning that the new element will be enqueued at the 5th index.

Lastly, rear is incremented by 1 to denote the new position where new element can be added.

6 0
3 years ago
How many comparisons will be made to find 8 in this list using a linear search?
Kobotan [32]

Answer:

4

Explanation:

4

6 0
2 years ago
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