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Julli [10]
3 years ago
8

The perimeter of a rectangular painting is 310 centimeters. If the width of the painting is 56 centim

Mathematics
2 answers:
gtnhenbr [62]3 years ago
7 0

Answer:

The length is 99 cm

Step-by-step explanation:

The perimeter of a rectangle is

P = 2 (l+w)

310 = 2( l+56)

Divide each side by 2

310/2 = 2/2( l+56)

155 = l+56

Subtract 56

155-56 = l+56-56

99 = l

stiv31 [10]3 years ago
5 0

Answer:

99 centimeters

Step-by-step explanation:

Use formula for perimeter of a rectangle.

P = 2l + 2w

310 = 2l + 2(56)

Solve for l.

310 - 2(56) = 2l

310 - 112 = 2l

198 = 2l

99 = l

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Step-by-step explanation:

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Which series is convergent? check all that apply. sigma-summation underscript n = 1 overscript infinity endscripts startfraction
ziro4ka [17]

These series show convergence of series which are

sigma-summation underscript n = 1 overscript infinity endscripts startfraction 2 n over n 1 endfraction

sigma-summation underscript n = 1 overscript infinity endscripts 3 (startfraction 1 over 10 endfraction)

According to the statement

we have given the some series and we have to find that the out of these series which series is convergent.

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we know that the for the convergent of series there is a one condition and if those condition will satisfy on the series then the series is convergent and if not then series is divergent.

So, the condition for convergent is a series converges if the absolute value of the sum of any finite number of sequential terms can become arbitrary small by starting the addition from a term which is far enough. So, if this condition is not satisfied the series diverges.

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  • sigma-summation underscript n = 1 overscript infinity endscripts 3 (startfraction 1 over 10 endfraction)

So, These series show convergence of series  which are

sigma-summation underscript n = 1 overscript infinity endscripts startfraction 2 n over n 1 endfraction

sigma-summation underscript n = 1 overscript infinity endscripts 3 (startfraction 1 over 10 endfraction)

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